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emmainna [20.7K]

3 years ago

15

Javier’s fuel tank holds 12 3⁄4 gallons of gasoline when completely full. He had some gas in the tank and added 10.3 gallons of

gasoline to fill it completely.
How many gallons of gasoline were in the tank before Javier added some?

1 answer:

Tju [1.3M]3 years ago

5 0

2 2/3 because i am good with fractions
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PLEASE HELP! Find the missing part.

viktelen [127]

Answer:

Step-by-step explanation:

$\frac{y}{a}= tan~60=\sqrt{3} \\y=a\sqrt{3} ~~~(1)\\\frac{y}{b} =tan~30\\y=\frac{b}{\sqrt{3} } ~~~(2)\\from~(1)~and~(2)\\a\sqrt{3} =\frac{b}{\sqrt{3} } \\b=a\sqrt{3} \times\sqrt{3} =3a\\a+b=15\\a+3a=15\\4a=15\\a=\frac{15}{4} \\b=3a=3 \times \frac{15}{4} =\frac{45}{4}\\y=a\sqrt{3} =\frac{15\sqrt{3}}{4} \\\frac{x}{15} =sin~30\\x=15 \times \frac{1}{2}=\frac{15}{2}\\\frac{z}{15}=cos~30\\z=15 \times \frac{\sqrt{3}}{2}=\frac{15\sqrt{3} }{2} \\$

4 0

3 years ago

3. At the mission museum Mrs. Perez visited over break, there is a pond like the one below that has a ring-shaped sidewalk aroun

yarga [219]

Answer:

(a) $36\pi \ m^2$

(b) $113.04\ m^2$

Step-by-step explanation:

(a) Write and simplify an expression for the exact area of the sidewalk.

(b) Find the approximate area of the sidewalk. Use 3.14 to approximate .

(a) The sidewalk area is the difference in the area of outer circle and inner circle.

Use formula $A=\pi r^2$ for the area of the circle:

$A_{outer}=\pi \cdot 10^2=100\pi \ m^2\\ \\A_{inner}=\pi \cdot 8^2=64\pi \ m^2$

The difference is

$A_{Sidewalk}=A_{outer}-A_{inner}=100\pi -64\pi =36\pi \ m^2$

(b) Use approximation $\pi \approx 3.14,$ then

$A_{Sidewalk}\approx 36\cdot 3.14=113.04\ m^2$

4 0

3 years ago

-3v-2=-2-8v+5v How many solutions? Will mark brainlest

Jet001 [13]

Answer:

infinite solutions

Step-by-step explanation:

-3v-2=-2-8v+5v

Combine like terms

-3v-2 = -2 -3v

Add 3v to each side

-3v-2+3v = -2 -3v+3v

-2 = -2

Since this is always a true statement, there are infinite solutions

5 0

3 years ago

Maria wants to solve the following system using the elimination method:

prohojiy [21]

In order to eliminate the y terms, the y terms must be reciprocals.
The first equation has 9y.
To eliminate y, you need to add to it -9y.
The second equation has y. In order for the second equation to have -9y, you must multiply both sides of the second equation by -9.

Answer: D -9

7 0

3 years ago

Solve the following system: 5x + 4y = 6 -2x – 3y = -1

yanalaym [24]

Answer:

$\left \{ {{y=-1} \atop {x=2}} \right.$

Step-by-step explanation:

$\left \{ {{5x+4y=6} \atop {-2x-3y=-1}} \right. \left \{ {{10x+8y=12} \atop {-10x-15y=-5}} \right. \left \{ {{-7y=7} \atop {-10x-15y=-5}} \right. \left \{ {{y=-1} \atop {-10x-15y=-5}} \right. \left \{ {{y=-1} \atop {-10x+15=-5}} \right. \left \{ {{y=-1} \atop {-10x=-20}} \right. => \left \{ {{y=-1} \atop {x=2}} \right.$

3 0

2 years ago