<img src="https://tex.z-dn.net/?f=y%20%3D%202x%20-%2011%20%5C%5C%204x%20%2B%203y%20%3D%20%20-%2013" id="TexFormula1" title="y =

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3 years ago

2x - 11 \\ 4x + 3y = - 13" alt="y = 2x - 11 \\ 4x + 3y = - 13" align="absmiddle" class="latex-formula">
How do u solve this system equation?

Mathematics

2 answers:

leva [86]3 years ago

7 0

y = 2x - 11

4x + 3y = -13

To solve this system using substitution, substitute (2x - 11) into the second equation for y and solve algebraically for x.

4x + 3y = -13 (given)

4x + 3(2x - 11) = -13 (substitute)

4x + 6x - 33 = -13 (distribute)

10x - 33 = -13 (collect like terms)

10x = 20 (add 33 to both sides)

x = 2 (divide both sides by 10)

Substitute 2 for x into either of the original equations.

y = 2x - 11 (given)

y = 2(2) - 11 (substitute)

y = 4 - 11 (multiply)

y = -7 (subtract)

Answer:

x = 2 and y = -7; (2, -7).

PSYCHO15rus [73]3 years ago

4 0

I think that
y = -7
x= 2

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