U cant simplify it, this fraction 11/40 is simplified to the max.
Area: Trapezoids A = ½h(b1<span> + b</span>2<span>)
</span>Rhombuses A=pq/2
Kites A=pq/2
For this case we have that the weight of the bouquet of flowers will be:
4.3 * 10 ^ 4 - 2 * (7.5 * 10 ^ 2)
Rewriting we have:
4.1 * 10 ^ 4 miligrams
Thus, we have that the values of p and q are given by:
p = 4.1
q = 4
Answer:
4.1 * 10 ^ 4 miligrams
p = 4.1
q = 4
After each hour 60% ( or 0.60) of the drug will be present.
The equation is A = 100(0.6)^t where t = time in hours. (answer)
