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2 years ago

A bat and a ball cost one dollar and ten cents in total. The bat costs a dollar more than the ball. How much does the ball cost?

Mathematics

1 answer:

Marrrta [24]2 years ago

3 0

Answer:10 cents

Step-by-step explanation:you said that the bat cost dollar,so it means that the ball have to cost ten cents

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How many solutions exist for the given equation? 3x 13 = 3(x 6) 1 zero one two infinitely many

romanna [79]

An equation is formed of two equal expressions. There is no solution set of the equation 3x+13 = 3(x+6)+1.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The equation can be solved in the following manner,

$3x+13 = 3(x+6)+1\\3x+13=3x+18+1\\3x+13=3x+19$

Since both the sides of the equation are the same in terms of variable and the constant terms are not the same. Therefore, there is no solution set of the equation 3x+13 = 3(x+6)+1.

Learn more about Equation:

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1 year ago

Chelsea wants to rearrange her room. She makes a scale drawing of the room and cuts out

oee [108]

Answer:I think it is the First one

Step-by-step explanation:

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3 years ago

Which of the following expressions has a value of 3? Select all that apply.

Tpy6a [65]

It would be (-1)(-3) :))

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2 years ago

Plllzzz im new and i neeed help

ella [17]

Answer:

4082

Step-by-step explanation:

Given

The composite object

Required

The volume

The object is a mix of a cone and a hemisphere

Such that:

$r = 10cm$ ---- radius (r = 20/2)

$h = 19cm$

<u>Hemisphere</u>

$r=10cm$

The volume of the cone is:

$V_1 = \frac{1}{3}\pi r^2h$

$V_1 = \frac{1}{3}\pi * 10^2 * 19$

$V_1 = \frac{1900}{3}\pi$

The volume of the hemisphere is:

$V_2 = \frac{2}{3}\pi r^3$

$V_2 = \frac{2}{3}\pi 10^3$

$V_2 = \frac{2000}{3}\pi$

So, the volume of the object is:

$V = V_1 + V_2$

$V = \frac{1900}{3}\pi + \frac{2000}{3}\pi$

$V = \frac{3900}{3}\pi$

$V = 1300\pi$

$V = 1300 * 3.14$

$V = 4082$

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3 years ago

Ken earned 128 from his part time summer job

Naya [18.7K]

You are missing part of the question

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2 years ago