Sooooooooo technically i've neevr lost a fight with a tiger

Is it allowed to drift on the streets of Tokyo?

Anon25 [30]

Yes ding ding ding ding ding ding

4 0

3 years ago

Prove this 1-tan^2x/1+tan^2x=cos^2x-sin^2x

tatiyna

Answer:

see explanation

Step-by-step explanation:

Using the identity

tan x = $\frac{sinx}{cosx}$

Consider the left side

$\frac{1-tan^2x}{1+tan^2x}$

= $\frac{1-\frac{sin^2x}{cos^2x} }{1+\frac{sin^2x}{cos^2x} }$ ( multiply numerator and denominator by cos²x to clear fractions

= $\frac{cos^2x-sin^2x}{cos^2x+sin^2x}$ ← ( cos²x + sin²x = 1 ]

= cos²x - sin²x

= right side , thus proven

7 0

3 years ago

Please answer this question now in two minutes

saw5 [17]

Answer:

12

Step-by-step explanation:

18 - 27 - 90 = 63 degrees. Special thingy so answer is above

6 0

3 years ago

In a survey of 1000 randomly selected adults in the United States, participants were asked what their most favorite and what the

xenn [34]

Answer:

(a) The 95% confidence interval for the population proportion of US adults for whom math was their most favorite subject is (0.204, 0.256).

(b) The 95% confidence interval for the population proportion of US adults for whom math was their least favorite subject is (0.34, 0.40).

Step-by-step explanation:

The questions are:

(a) Construct and interpret a 95% confidence interval for the proportion of US adults for whom math was their most favorite subject.

(b) Construct and interpret a 95% confidence interval for the proportion of US adults for whom math was their least favorite subject. Solution:

(a)

The 95% confidence interval for the population proportion is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Th information provided is:

n = 1000

Number of US adults for whom math was their most favorite subject

= X

= 230

Compute the sample proportion of US adults for whom math was their most favorite subject as follows:

$\hat p=\frac{230}{1000}=0.23$

The critical value of z for 95% confidence interval is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for the population proportion of US adults for whom math was their most favorite subject as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.23\pm 1.96\sqrt{\frac{0.23(1-0.23)}{1000}}\\=0.23\pm 0.0261\\=(0.2039, 0.2561)\\\approx (0.204, 0.256)$

Thus, the 95% confidence interval for the population proportion of US adults for whom math was their most favorite subject is (0.204, 0.256).

(b)

The 95% confidence interval for the population proportion is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Th information provided is:

n = 1000

Number of US adults for whom math was their least favorite subject

= X

= 370

Compute the sample proportion of US adults for whom math was their least favorite subject as follows:

$\hat p=\frac{370}{1000}=0.37$

The critical value of z for 95% confidence interval is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for the population proportion of US adults for whom math was their least favorite subject as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.37\pm 1.96\sqrt{\frac{0.37(1-0.37)}{1000}}\\=0.37\pm 0.0299\\=(0.3401, 0.3999)\\\approx (0.34, 0.40)$

Thus, the 95% confidence interval for the population proportion of US adults for whom math was their least favorite subject is (0.34, 0.40).

8 0

3 years ago

If m A.26° B.42° C.112° D.124°

loris [4]

Is is the b becuase is b

3 0

3 years ago