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3 years ago

Sooooooooo technically i've neevr lost a fight with a tiger

Mathematics

1 answer:

Aloiza [94]3 years ago

3 0

Answer:

oh thats cool

Step-by-step explanation:

You might be interested in

How to solve 3+p=8 step by step

AURORKA [14]

3+p=8
-p -p
3=8-p
-8 -8
-5=-p
swap signs
5=p

5 0

3 years ago

Read 2 more answers

Which point could be on the line that is perpendicular

slamgirl [31]

Answer:

b (2,2)

Step-by-step explanation:

4 0

3 years ago

Sketxh the graph of y=(x+3)^3 and state the points where the graph crosses the axes

gtnhenbr [62]

Answer: the graph crosses the x-axis at x = -3

Step-by-step explanation:

y = (x + 3)³

To find where the graph crosses the x-axis, let y = 0 and solve for x:

0 = (x + 3)³

0 = (x + 3) with a multiplicity of 3

-3 = x with a multiplicity of 3.

Since multiplicity is an ODD number, the graph CROSSES the x-axis at x = -3

Graph:

Leading coefficient is POSITIVE so right side goes to +∞
Degree of polynomial is ODD so left side goes to -∞

graph is attached

6 0

3 years ago

Help with the 1st one and Second one.

gayaneshka [121]

132 feet per second

And

66 feet in half a second

Your welcome...

6 0

3 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

harina [27]

$L(x,y,z,\lambda)=8x+8y+4z+\lambda(4x^2+4y^2+4z^2-36)$

$L_x=8+8\lambda x=0\implies 1+\lambda x=0$
$L_y=8+8\lambda y=0\implies 1+\lambda y=0$
$L_z=4+8\lambda z=0\implies 1+2\lambda z=0$
$L_\lambda=4x^2+4y^2+4z^2-36=0\implies x^2+y^2+z^2=9$

$yL_x=y+\lambda xy=0$
$xL_y=x+\lambda xy=0$
$\implies yL_x-xL_y=y-x=0\implies y=x$

$2zL_x=2z+2\lambda xz=0$
$xL_z=x+2\lambda xz=0$
$\implies 2zL_x-xL_z=2z-x=0\implies x=2z$

$2zL_y=2z+2\lambda yz=0$
$yL_z=y+2\lambda yz=0$
$\implies 2zL_y-yL_z=2z-y=0\implies y=2z$

$x=y=2z\implies x^2+y^2+z^2=9\iff 4z^2+4z^2+z^2=9z^2=9\implies z=\pm1$

$z=\pm1\implies y=x=\pm2$

So we have two critical points, (2, 2, 1) and (-2, -2, -1), which respectively give a max of 36 and a min of -36.

5 0

3 years ago