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3 years ago

How is the expression (5 + y) ⋅8 described by its factors and terms?

1 answer:

8 0

Answer: Choice D
It has two factors and the factor (5+y) has two terms

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Explanation:

(5+y)*8 is in the form P*Q where
P = 5+y
Q = 8
So we have two factors multiplied together. A factor is simply a number that helps multiply to a larger one. Another example: 14 has the factors 7 and 2 because 7*2 = 14

The factor 5+y has two terms which are 5 and y. The terms are separated by a plus sign. If you had something like 5-y, then you can write it as 5+(-y) and you'd still have two terms.

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On the blueprint of a house, 42 millimeters represents 8 meters. The actual length of the living room is 5 meters. What is its l

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Answer:

26.25 mm

Step-by-step explanation:

On the blueprint of a house, 42 millimeters represents 8 meters. Thus,

42 mm - 8 m,

x mm - 5 m,

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

-4(9n + 9) = -12(4n - 6).

WITCHER [35]

Answer:

n = 9

Step-by-step explanation:

Step 1: Write equation

-4(9n + 9) = -12(4n - 6)

Step 2: Solve for n

Distribute: -36n - 36 = -48n + 72

Add 48n to both sides: 12n - 36 = 72

Add 36 to both sides: 12n = 108

Divide both sides by 12: n = 9

Step 3: Check

Plug in n to verify if it's a solution.

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3 years ago

A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a

Rashid [163]

Answer:

Length of original rectangle: 11 units.

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

$\text{Perimeter of new rectangle}=20$

Step-by-step explanation:

Let x represent width of the original rectangle.

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be $x+6$ .

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be $x-2$ .

The length of new rectangle would be $x+6-4=x+2$ .

The area of new rectangle would be $(x+2)(x-2)$ .

Now we will equate area of new rectangle with 21 and solve for x as:

$(x+2)(x-2)=21$

Applying difference of squares, we will get:

$x^2-2^2=21$

$x^2-4=21$

$x^2-4+4=21+4$

$x^2=25$

Since width cannot be negative, so we will take positive square root of both sides.

$\sqrt{x^2}=\sqrt{25}$

$x=5$

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be $x+6\Rightarrow x+5=11$ .

Therefore, the length of original rectangle is 11 units.

$\text{Area of original rectangle}=5\times 11$

$\text{Area of original rectangle}=55$

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

We know that perimeter of rectangle is two times the sum of length and width.

$\text{Perimeter of new rectangle}=2((x+2)+(x-2))$

$\text{Perimeter of new rectangle}=2((5+2)+(5-2))$

$\text{Perimeter of new rectangle}=2(7+3)$

$\text{Perimeter of new rectangle}=2(10)$

$\text{Perimeter of new rectangle}=20$

Therefore, the perimeter of the new rectangle is 20 units.

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4 years ago