What's 1.2 times 0.12?!?!

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

You have just timed a person doing a hair cut for the first time. It took 50 minutes. What unit improvement factor learning curv

Sladkaya [172]

Answer: C. 70 percent

Step-by-step explanation:

Given, Time for the first unit = 50 minutes

Time for the second unit = 35 minutes

The unit improvement factor learning curve = (The time for the second unit) ÷ (time for the first unit) x 100.

So, The unit improvement factor learning curve = 35÷ 50 × 100 = 70 percent.

Hence, the correct option is "C. 70 percent".

3 0

2 years ago

What is the sum of: Days in the week + Months or

Lemur [1.5K]

7+ 30 or 31 or 28 or 29 not sure that's what ur asking for

5 0

2 years ago

Correct answers onlyy !

77julia77 [94]

Answer:

D

Step-by-step explanation:

a substance made by mixing other substances together.

8 0

2 years ago

John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs

mezya [45]

Answer:

The number of Pumpkin can used = 48 cans

The number of Green Beans can used = 16 cans

Step-by-step explanation:

The ratio of Pumpkin to Green Beans = 3 : 1

So, for every 3 can of Pumpkin, 1 can of green beans is used.

Now, the total number of John wants to use = 64

Let us assume the common factor in the ratio is m.

⇒ The number of Pumpkin can used = 3 m

The number of Green Beans can used = 1 m = m

So, the Total cans used = Number of (Pumpkin + Green Beans) can

⇒ 3 m + m = 64

or, 4 m = 64

⇒ m = 64/ 4 = 16

Hence, The number of Pumpkin can used = 3 m = 3 x 16 = 48 cans

The number of Green Beans can used = m = 16 cans

3 0

3 years ago