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vitfil [10]
2 years ago
10

Draw a rectangle that is 3 squares long and 1/2 of a square wide. Then add up the partial squares to find the area. Multiply to

check your answer.

Mathematics
2 answers:
nataly862011 [7]2 years ago
7 0

Answer:

3/2 or 1 1/2 squares.

Step-by-step explanation:

It says it on the image attached. Also, it's what you get when you multiply

3*\frac{1}{2}.

DerKrebs [107]2 years ago
5 0
<h3>Explanation:</h3>

P.S: <u>Rectangle attached in image.</u>

According to the image, we can see that 3 rectangles are <u>half shaded.</u>

<u>This means that:</u>

  • Half shaded square + Half shaded square + Half shaded square
  • => 0.5 + 0.5 + 0.5
  • => 1.5 units²
<h3>Check:</h3>

<u>To check our answer:</u>

  • 3 x 0.5 = Area of rectangle
  • => 1.5 units² = Area of rectangle

Hence, our explanation is <u>correct.</u>

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An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.
andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are E(1)= ^9C_2 places in which the other 2 red balls can be placed.

A red ball drawn third, there are E(3)= ^7C_2 places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are E(5)= ^5C_2 places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are E(7)= ^3C_2 places in which the other 2 red balls can be placed.

The total number of total event is S= ^{10}C_3

The probability that A selects the first red ball is

P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}

P(A \text{wins})=\frac{36+21+10+3}{120}

P(A \text{wins})=\frac{70}{120}

P(A \text{wins})=0.5833

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