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vitfil [10]
2 years ago
10

Draw a rectangle that is 3 squares long and 1/2 of a square wide. Then add up the partial squares to find the area. Multiply to

check your answer.

Mathematics
2 answers:
nataly862011 [7]2 years ago
7 0

Answer:

3/2 or 1 1/2 squares.

Step-by-step explanation:

It says it on the image attached. Also, it's what you get when you multiply

3*\frac{1}{2}.

DerKrebs [107]2 years ago
5 0
<h3>Explanation:</h3>

P.S: <u>Rectangle attached in image.</u>

According to the image, we can see that 3 rectangles are <u>half shaded.</u>

<u>This means that:</u>

  • Half shaded square + Half shaded square + Half shaded square
  • => 0.5 + 0.5 + 0.5
  • => 1.5 units²
<h3>Check:</h3>

<u>To check our answer:</u>

  • 3 x 0.5 = Area of rectangle
  • => 1.5 units² = Area of rectangle

Hence, our explanation is <u>correct.</u>

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FIND THE VOLUME OF A PRISM-SHAPED WATERMELON IN CUBIC INCHES IF ITS LENGTH IS 10 INCHES ITS WIDTH IS 2/3 FOOT AND ITS HIEGHT IS
svetlana [45]
The way to find Volume is V=lwh so plug in the length, width and height( V=(10)x(2/3)x(9) ) and you'll get your answer.
4 0
3 years ago
Please help me with this quick :))))))))
vredina [299]

Answer:

129.3 in²

Step-by-step explanation:

The shaded segment is calculated as

area of sector ABC - area of triangle ABC

area of sector = area of circle × fraction of circle

A = πr² × \frac{60}{360}

   = π × 18² × \frac{1}{6}

   = 324π × \frac{1}{6} = 54π in²

area of Δ ABC = \frac{1}{2} × 18 × 18 × sin60°  ≈ 40.30 in²

Then

shaded area = 54π - 40.30 ≈ 129.3 in² ( to the nearest tenth )

6 0
2 years ago
) Solve this equation: − 10 + = 8 + 2 − 18
nikitadnepr [17]

Answer:

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4 0
2 years ago
The diagram shows the entrance to a tunnel.
gladu [14]

Step-by-step explanation:

it filled up half the circle (up to the center point) - if we had a full circle. but a little bit is cut off (below AB).

what we see is that the shaded area is the sum of the area of the triangle AOB and 2 equally sized circle segment areas left and right of AOB.

since we are dealing with a half-circle, we have 180° in total. 120° are taken by AOB, so, that leaves us with 180-120 = 60° for both circle segments (so, one has an angle of 30°).

and 2×30° = 1×60°, so we can calculate the area of one 60° segment instead of two 30° segments.

AOB is an isoceles triangle (the legs are equally long, and therefore also the 2 side angles are equal).

the area of this triangle AOB is

1/2 × a × b × sin(C) = 1/2 × 3 × 3 × sin(120) =

= 3.897114317... m²

a circle segment area of 60° is 60/360 = 1/6 of the full circle area (as a full circle = 360°).

so, it's area is

pi×r² × 1/6 = pi×3²/6 = pi×3/2 = 4.71238898... m²

so, the total area of the shaded area is

3.897114317... m² + 4.71238898... m² =

= 8.609503297... m²

5 0
2 years ago
5h+3 - j; use h = 6, and j = 1
olga55 [171]

Answer:

32

Step-by-step explanation:

lets substitute the appropriate values in the equation:

5h+3 - j    h= 6    j=1 , so we have:

5*6 +3 -1

30 +3 -1

32

7 0
3 years ago
Read 2 more answers
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