The way to find Volume is V=lwh so plug in the length, width and height( V=(10)x(2/3)x(9) ) and you'll get your answer.
Answer:
129.3 in²
Step-by-step explanation:
The shaded segment is calculated as
area of sector ABC - area of triangle ABC
area of sector = area of circle × fraction of circle
A = πr² × 
= π × 18² × 
= 324π ×
= 54π in²
area of Δ ABC =
× 18 × 18 × sin60° ≈ 40.30 in²
Then
shaded area = 54π - 40.30 ≈ 129.3 in² ( to the nearest tenth )
Answer:
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Step-by-step explanation:
it filled up half the circle (up to the center point) - if we had a full circle. but a little bit is cut off (below AB).
what we see is that the shaded area is the sum of the area of the triangle AOB and 2 equally sized circle segment areas left and right of AOB.
since we are dealing with a half-circle, we have 180° in total. 120° are taken by AOB, so, that leaves us with 180-120 = 60° for both circle segments (so, one has an angle of 30°).
and 2×30° = 1×60°, so we can calculate the area of one 60° segment instead of two 30° segments.
AOB is an isoceles triangle (the legs are equally long, and therefore also the 2 side angles are equal).
the area of this triangle AOB is
1/2 × a × b × sin(C) = 1/2 × 3 × 3 × sin(120) =
= 3.897114317... m²
a circle segment area of 60° is 60/360 = 1/6 of the full circle area (as a full circle = 360°).
so, it's area is
pi×r² × 1/6 = pi×3²/6 = pi×3/2 = 4.71238898... m²
so, the total area of the shaded area is
3.897114317... m² + 4.71238898... m² =
= 8.609503297... m²
Answer:
32
Step-by-step explanation:
lets substitute the appropriate values in the equation:
5h+3 - j h= 6 j=1 , so we have:
5*6 +3 -1
30 +3 -1
32