Answer:
1/4
Explanation:
Cystic fibrosis is a recessive disorder and therefore, is expressed only in homozygous recessive genotype. Let's assume that the allele "c" is responsible for the disease in the homozygous state. Since the couple already has a child with cystic fibrosis (cc), they both are heterozygous carriers for the disease.
The genotype of male and female each is "Cc". A cross between Cc x Cc gives progeny in the following phenotype ratio=1/4 diseased: 1/2 normal carriers: 1/4 normal. Therefore, the probability of getting a diseased child for them is 1/4.
Answer:
RNA polymerase
The main enzyme involved in transcription is RNA polymerase, which uses a single-stranded DNA template to synthesize a complementary strand of RNA.
Explanation:
The quiescent center is the mitotically inactive portion of the root tip that acts as a reserve of healthy cells in case the apical meristem becomes damaged.
Quiescent center cells exhibit high resistance to ionizing radiation, especially when compared to surrounding initial cells, leading to the hypothesis that the quiescent center functions as a stem cell reservoir, ensuring the rejuvenation and perseverance of the root apical meristem.
The root quiescent center is a pool of rarely dividing stem cells inside the root apical meristem. The Quiescent center maintains the environment more regularly by dividing initials, forming the root apical meristem cell niche.
To learn more about the quiescent center: brainly.com/question/411841
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Broca's area is in the frontal lobe. Wernikes is in the temporal lobe.
If a white female cat and a black male cat produce offspring that are both black and white, this is an example of codominance. The reason for this is that a person who has A allele and a person who have B allele will have blood type AB.
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