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mart [117]
3 years ago
12

Can someone please help me with angle measurements?!

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0
Ya i can help you whats up 

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What is the period, in seconds, of a simple pendulum of length 2 meters? Use the gravitational constant g = 9.8 m/s^2 and round
kirill [66]

Answer:

The period, in seconds to two decimal places is, 2.84 sec

Step-by-step explanation:

Using formula:

T = 2 \pi \sqrt{\frac{l}{g}}             ......[1]

where

T represents the Time period in second

l represents the length of the pendulum/

As per the statement:

Use the gravitational constant g = 9.8 m/s^2 , length of the simple pendulum(l) = 2 meters and \pi = 3.14

Substitute the given values we have;

T = 2\cdot 3.14 \cdot \sqrt{\frac{2}{9.8}}

⇒T = 6.28 \cdot \sqrt{\frac{1}{4.9}}=6.28 \cdot \frac{1}{2.21359436212}= \frac{6.28}{2.21359436212} = 2.83701481512

Therefore, the period, in seconds to two decimal places is, 2.84 sec

8 0
3 years ago
Help<br><br><br><br><br><br> Thrhfjfhfhhfhfhfjf
12345 [234]

Answer: 5

Step-by-step explanation:

a^2 + b^2 = c^2

12^2 + x^2 = 13^2

144 + x^2 = 169

x^2 = 25

square root both sides

x = 5

to check, do 12^2 + 5^2 =169

sqrt of 169 is 13

hope this helps

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3 years ago
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weeeeeb [17]

Answer:

15/32 in fraction form. 3/4 x 5/8 = 0.4688 in decimal form.

Step-by-step explanation:

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3 years ago
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8x=6x+20 Btw I figures it out x=10
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4 years ago
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