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Reptile [31]
3 years ago
5

What is the Evaluation

Mathematics
1 answer:
Ede4ka [16]3 years ago
3 0

Answer:

work is shown and pictured

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the total cost for two items is $19 is the difference in the cost of the two items is $5 find the cost of each item.
lora16 [44]

Ok so you spent 19 dollars the difference between prices is 5 dollars and your answer would be 12 and 7. If you need any help let me know.

5 0
3 years ago
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Circle O has a circumference of approximately 250π ft
liraira [26]

Answer:

79.617...

Step-by-step explanation:

When you are trying to find the circumfrence you do c=πd

So to find the diameter you reverse it

Since you already know the 250 feet you divide it by π

You then get 79.6

5 0
3 years ago
What is 832 times 1 equal to?
denpristay [2]

Answer:

832

Step-by-step explanation:

If you have one group of 832, and put it into 1 group you get 832

8 0
2 years ago
The diagonal of rectangle ABCD measures 2 inches in length What is the length of line segment AB?
sesenic [268]
Unfortunately, this item does not come with any figure to illustrate the lengths of the rectangle. However, it may be noted that by connecting two opposite vertices of a rectangle by a diagonal, we form a right triangle. We may then use the Pythagorean theorem to solve for the answer. 
                                     a² + b² = c²
c in this equation is the length of the diagonal, a and b are the lengths of the sides. 
6 0
3 years ago
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The Cunninghams are moving across the country. Mr. Cunningham leaves 3 hours before Mrs. Cunningham. If he averages 40mph and sh
svp [43]
Recall your d = rt, distance = rate * time

now, if say, by the time they meet, Mr Cunningham has travelled "d" miles, that means Mrs Cunningham must also had travelled "d" miles as well.

However, he left 3 hours earlier, so by the time he travelled "d" miles, and took say "t" hours, for her it took 3 hour less, because she started driving 3 hours later, so, she's been on the road 3 hours less than Mr Cunningham, so by the time they meet, Mrs Cunningham has travelled then "t - 3" hours.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Mr Cunningham}&d&40&t\\
\textit{Mrs Cunningham}&d&80&t-3
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=40t\\
d=80(t-3)\\
----------\\
\boxed{40t}=80(t-3)
\end{cases}
\\\\\\
\cfrac{40t}{80}=t-3\implies \cfrac{t}{2}=t-3\implies t=2t-6\implies 6=2t-t
\\\\\\
6=t
5 0
3 years ago
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