Consider sending a 1,600-byte datagram into a link that has an mtu of 500 bytes. suppose the original datagram is stamped with t
1 answer:
Explanation:
Step one
The maximum size of data field in each fragment = 480
(because there are 20 bytes IP header) Thus the number of required
fragments
thus the number of required fragment is 4
Step two
Each fragment will have identification number 291. each fragment except the last one will be of size 500 bytes (including IP header). the offset of the fragments will be 0, 60, 120, 180. each of the first 3 fragments will have
flag = 1; the last fragment will have flag =0
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Answer:
View image below.
Explanation:
They're just asking you to create a num2bin function on Cpp.
If you search for "num2bin in C", you can find a bunch of answers for this if you think my solution is too confusing.
One way to do it is the way I did it in the picture.
Just copy that function and use it in your program. The rest you can do yourself.
