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Radda [10]
3 years ago
8

Performance Task Review 1

Mathematics
1 answer:
wariber [46]3 years ago
7 0

Answer: a = 5; b = 5; c = 10; d = 5\sqrt{3}; e = 5\sqrt{2}; f = 6.93; g = 13

A_{H} = 12.5; A_{J} = 55; A_{K} = 12.5\sqrt{3}; A_{L} = 38.1

Step-by-step explanation:

<u>Value of e</u>:

sin 45 = \frac{5}{e}

e = 5.\frac{2}{\sqrt{2} }

e = 5\sqrt{2}

<u>Value of a:</u>

e² = 5² + a²

a = \sqrt{ (5\sqrt{2} )^{2} - 5^{2} }

a = 5

<u>Value of b</u>:

The figure J is a rectangle, so opposite sides have the same value. Since b is opposite side of the side measuring 5, b = 5.

<u>Value of c:</u>

sin 30 = \frac{5}{c}

c = 5. 2

c = 10

<u>Value of d</u>:

cos 30 = \frac{d}{10}

d = 10.\frac{\sqrt{3} }{2}

d = 5\sqrt{3}

<u>Value of g</u>:

cos 56 = \frac{11}{g}

g = \frac{11}{0.8532}

g = 13

<u>Value of f</u>:

g² = 11² + f²

f = \sqrt{169 - 121}

f = 7

<u>Area of H:</u>

A_{H} = \frac{5.5}{2}

A_{H} = 12.5

<u>Area of J:</u>

A_{J} = 11.5

A_{J} = 55

<u>Area of K:</u>

A_{K} = \frac{5\sqrt{3}.5 }{2}

A_{K} = 12.5\sqrt{3}

<u>Area of L:</u>

A_{L} = \frac{11.7}{2}

A_{L} = 38.5

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