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stiv31 [10]
2 years ago
15

In 2013, the population of the state of New York was approximately 19.65 million, and the population of New York City was 8,406,

000. In 2013, how many people in New York state did not live in New York City?
The answer in standard notation is
. The answer in scientific notation is p × 10q, where p is
and q is
Mathematics
1 answer:
maks197457 [2]2 years ago
7 0
Population of the state of New York is 19.65 million. 
Million is equal to 1*10^6
So 19.65*10^6

Population of New York city is 8,406,000.
It is equal to 8.406*10^6

Therefore people in New York state did not in New York city is,
19.65*10^6 - 8.406*10^6
11.244*10^6
1.1244*10^7
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A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 5​% will need repairs​
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Answer:

a) 0.5476

b) 0.0676

c) 0.4524

Step-by-step explanation:

Given this information, we can conclude that 74% of the cars won't need any repairs over a 1-year period (100 - 20 - 5 - 1 = 74%). And 26% will need at least 1 repair over a 1-year period.

P(car doesn't need repair) = 0.74

P (car needs repair) = 0.26

If you own two cars, the probability that:

<u>a) Neither will need repair:</u>

We need that car 1 won't need repair AND car 2 won't need repair.

=P(Car 1 doesn't need repair) x P(Car 2 doesn't need repair)

= 0.74 x 0.74 = 0.5476

The probability that neither will need repair is 0.5476.

<u>b) Both will need repair:</u>

We need that car 1 needs repair AND car 2 needs repair.

P(Car 1 needs repair) x P(Car 2 needs repair)

= 0.26 x 0.26 = 0.0676

The probability that both will need repair is 0.0676

<u>c) At least one car will need repair</u>

Car 1 needs repair or Car 2 needs repair or both need repair.

To solve this one, it's easier to use the complement of P(neither needs repair)

1 - P(neither needs repair)

1 - (0.74)(0.74)  = 1 - 0.5476 = 0.4524

The probability that at least one car will need repair is 0.4524

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Step-by-step explanation:

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