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3 years ago

5

Consider the solid formed by rotating a 2 x 3 rectangle with vertices (2,0), (4,0), (2,3), and (4,3) about the y-axis select all

the statements that are true about the resulting figure.
It will be a rectangle in the 3rd quadrant
It will be a solid cylinder with a radius of 2
It will be a hollow cylinder, the central core has a radius of 2
It will have a surface area equal to 56pi
It will have a surface area equal to 48pi

1 answer:

Liono4ka [1.6K]3 years ago

3 0

Answer: It will be a hollow cylinder, the central core has a radius of 2 and It will have a surface area equal to 48pi

Step-by-step explanation:

Just did it on algebra nation

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

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Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

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3 years ago

Find the oth term of the geometric sequence 9, -18, 36, ...

Sphinxa [80]

Answer:

2304

Step-by-step explanation:

<u>Given :- </u>

A geometric sequence is given to us which is 9 , -18 , 36.

And we need to find out the 9th term of the sequence. Here firstly we should find the Common Ratio and then we can substitute the respective values in the formula to find the nth term of a geometric sequence .

<u>Common Ratio :- </u>

$:\implies$ CR = -18÷ 9 = -2

<u>The </u><u>9</u><u> th term :- </u>

$:\implies$ T_n = arⁿ - ¹

$:\implies$ T_9 = 9× (-2) ⁹ - ¹

$:\implies$ T_9 = 9 × (-2)⁸

$:\implies$ T_9 = 9 × 256

$:\implies$ T_9 = 2304

<u>Hence the 10th term is </u><u>2</u><u>3</u><u>0</u><u>4</u><u>.</u>

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3 years ago