Find the value of a if d=80, v^0=50 and t=8
1 answer:
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Your question is incomplete, here is the complete form.
Points J, K and L are collinear with J between L and K. If KJ = 2x - 3, LK = 9x + 7 and LJ = 4x - 8, solve for x:
Answer:
The value of x is -6 ⇒ B
Step-by-step explanation:
∵ J, K, and L are collinear
→ That means they form a straight segment
∵ J is between K and L
→ That means J divides LK into two segments KJ and LJ
∴ LK = KJ + LJ
∵ LK = 9x + 7
∵ KJ = 2x - 3
∵ LJ = 4x - 8
→ Substitute them in the equation above
∴ 9x + 7 = (2x - 3) + (4x - 8)
→ Add the like terms in the right side
∵ 9x + 7 = (2x + 4x) + (-3 - 8)
∴ 9x + 7 = 6x + -11
∴ 9x + 7 = 6x - 11
→ Subtract 7 from both sides
∵ 9x + 7 - 7 = 6x - 11 - 7
∴ 9x = 6x - 18
→ Subtract 6x from both sides
∵ 9x - 6x = 6x - 6x - 18
∴ 3x = -18
→ Divide both sides by 3
∵
∴ x = -6
∴ The value of x is -6
To check if a piecewise defined function is continuous, you need to check how the pieces "glue" together when you step from one domain to the other.
So, the question is: what happens at x=3? If you reach x=3 from values slightly smaller than 3, you obey the rule f(x)=log(3x). So, as you approach 3, you get values closer and closer to
Similarly, if you reach x=3 from values slightly greater than 3, you obey the rule f(x)=(4-x)log(9). So, as you approach 3, you get values closer and closer to
So, the function is continuous at x=3, because both pieces approach log(9) as x approaches 3.