Two distinct number cubes are rolled together. Each number cube has sides numbered 1 through 6.

Someone help please i don’t want to fail math

VladimirAG [237]

Answer:

Image below!

Step-by-step explanation:

Plotting $\underline{y=2x+3}$

Step 1: determine the y-intercept

$(0,3)$

plot the point as the first point on the graph

Step 2: Move 2 units up, and 1 unit left (keep repeating this process until you have reached the limit of the graph)

Step 3: Go to the other side of the graph of the first point (y-intercept)

move 2 units down, and 1 unit right keep repeating this process until you have reached the limit of the graph)

When you've completed this process, it should look like this:

5 0

2 years ago

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

3 years ago

Who has insta im bored

nlexa [21]

wish i did, i'm bored as well

3 0

2 years ago

Read 2 more answers

Asked what the central limit theorem says, a student replies, As you take larger and larger samples from a population, the histo

Arada [10]

Answer:

A. No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means.

Step-by-step explanation:

No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means. The central limit theorem says that if we take a large sample (i.e., a sample of size n > 30) of any distribution with finite mean $\mu$ and standard deviation $\sigma$ , then, the sample average is approximately normally distributed with mean $\mu$ and variance $\sigma^2/n$ .

5 0

3 years ago

What could be concluded if the relative frequency of an event is equal to 1?

liubo4ka [24]

What could be concluded if the relative frequency of an event is equal to 1?

8 0

3 years ago