The direction vector of the line
L: x=1+t, y=4t, z=2-3t
is <1,4,-3>
which is also the required normal vector of the plane.
Since the plane passes through point (-5,9,10), the required plane is :
Π 1(x-(-5)+4(y-9)-3(z-10)=0
=>
Π x+4y-3z=1
Two inequalities are equivalent if they have the same set of solutions.
x - 5 ≤ 6 - 5
x - 5 ≤ 1 |add 5 to both sides
x ≤ 6
Answer:
The inequality that represents this situation is: 
Step-by-step explanation:
Since the plane already had 140 pounds on board and "n" boxes will be loaded on it, then the weigh of each box multiplied by the number of box should be the extra cargo on the plane. This extra cargo added to the previous load must be less than the limit of cargo the plane can take as shown below:
