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Nookie1986 [14]
3 years ago
13

Which is the graph of f(x) = StartRoot x EndRoot?

Mathematics
1 answer:
shusha [124]3 years ago
6 0

Answer:

The 4th graph

Step-by-step explanation:

To determine which graph corresponds to the f(x) = \sqrt{x}   we will start with inserting some values for x and see what y values we will obtain and then compare it with graphs.

f(1) = \sqrt{1} = 1\\f(2) = \sqrt{2} \approx 1.41\\f(4) = \sqrt{4} = 2\\f(9) = \sqrt{9} = 3

So, we can see that the pairs (1, 1), (2, 1.41), (4, 2), (3, 9) correspond to the fourth graph.

Do not be confused with the third graph - you can see that on the third graph there are also negative y values, which cannot be the case with the f(x) =\sqrt{x}, the range of that function is [0, \infty>,   so there are only positive y values for f(x) = \sqrt{x}

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(i) Given that

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(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

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V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

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In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

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Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

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