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3 years ago

What is the vertex of the function h(x) = |x + 6| + 3?

1 answer:

6 0

$\text{It absolute value equation nis represented as:}\\\\h(x)=a|x-h|+k\\\\\text{Where as h = x coordinate and k = y coordinate}\\\\\text{Now since we know this, find the vertex from:}\\\\h(x) = |x + 6| + 3\\\\\text{6 is in our h value, so that would be our x coordinate. Remember, it has}\\\text{to be the opposite value, so negative}\\\\(-6,k)\\\\\text{Now find k}\\\\\text{3 is our k value, so that'll be our y-coordinate. This one doesn't have to}\\\text{ahve its value changed}\\\\$

$\text{Therefore, your answer is:}\\\\\boxed{\text{B. (-6,3)}}$

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Multiply and divide Decimals

Tanzania [10]

Answer:

$57

Step-by-step explanation:

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2 years ago

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Bacteria can multiply at an alarming rate when each bacteria splits into two new cells, thus doubling. If we start with only one

Elan Coil [88]

Answer:

2^24 = 16,777,216 bacterias.

Step-by-step explanation:

So we start with 1 bacteria

after 1 hours: 2*1 = 2

after 2 hours: 2*2 = 2^2 = 4

after 3 hours: 2*2^2 = 2^3

after n hours: 2^n

Since one day has 24 hours we have n = 24 and total number of bacteria will

be: 2^24 = 16,777,216 bacterias.

5 0

3 years ago

A special type of door lock has a panel with five buttons labeled with the digits 1 through 5. This lock is opened by a sequence

belka [17]

There are several ways the door can be locked, these ways illustrate combination.

There are 3375 possible combinations

From the question, we have:

$\mathbf{n = 5}$ --- the number of digits

$\mathbf{r = 3}$ ---- the number of actions

Each of the three actions can either be:

Pressing one button
Pressing a pair of buttons

The number of ways of pressing a button is:

$\mathbf{n_1 = ^5C_1}$

Apply combination formula

$\mathbf{n_1 = \frac{5!}{(5-1)!1!}}$

$\mathbf{n_1 = \frac{5!}{4!1!}}$

$\mathbf{n_1 = \frac{5 \times 4!}{4! \times 1}}$

$\mathbf{n_1 = 5}$

The number of ways of pressing a pair is:

$\mathbf{n_2 = ^5C_2}$

Apply combination formula

$\mathbf{n_2 = \frac{5!}{(5-2)!2!}}$

$\mathbf{n_2 = \frac{5!}{3!2!}}$

$\mathbf{n_2 = \frac{5 \times 4 \times 3!}{3! \times 2 \times 1}}$

$\mathbf{n_2 = 10}$

So, the number of ways of performing one action is:

$\mathbf{n =n_1 + n_2}$

$\mathbf{n =5 + 10}$

$\mathbf{n =15}$

For the three actions, the number of ways is:

$\mathbf{Action = n^3}$

$\mathbf{Action = 15^3}$

$\mathbf{Action = 3375}$

Hence, there are 3375 possible combinations

Read more about permutation and combination at:

brainly.com/question/4546043

4 0

2 years ago

100% I don´t really understand this so plz help me

jeka94

Answer: I think it is greater than

Step-by-step explanation:

Because positive - negative = positive

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3 years ago

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Calculate the slope of a line the -1,2 and 0,8

krok68 [10]

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3 years ago

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