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3 years ago

Pls help me!! a= 2 / b= 3 / c= 5

Mathematics

2 answers:

kondaur [170]3 years ago

6 0

Answer:

1066

Step-by-step explanation:

Fill in the numbers for the letters

Solve in the parenthesis

Multiply

Subtract

Vesnalui [34]3 years ago

6 0

Answer:

1066

Step-by-step explanation:

substitute;

2×2^2×3^3×5 - 7×2

2×4×27×5 - 7×2

multiply;

1080 - 14 = 1066.

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The quotient of a number and 4 is less than -1

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x/4<-1

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Solve the system using elimination 2x+3y=14 x+5y=14

natali 33 [55]

Answer:

x = 4 , y = 2

Step-by-step explanation by elimination:

Solve the following system:

{2 x + 3 y = 14 | (equation 1)

x + 5 y = 14 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + 3 y = 14 | (equation 1)

0 x+(7 y)/2 = 7 | (equation 2)

Multiply equation 2 by 2/7:

{2 x + 3 y = 14 | (equation 1)

0 x+y = 2 | (equation 2)

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{2 x+0 y = 8 | (equation 1)

0 x+y = 2 | (equation 2)

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0 x+y = 2 | (equation 2)

Collect results:

Answer: {x = 4 , y = 2

4 0

3 years ago

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Almost 7/16 of thd total water supplied to a house hold is wasted because of leaky faucets. determine the decimal equivalent of

Lena [83]

Answer:

0.4375

Step-by-step explanation:

To find the decimal equivalent you have to divide the numerator by the denominator.

7 ÷ 16 = 0.4375

4 0

3 years ago

Solve.

Ksenya-84 [330]

Solve.

x² + 4x + 4 = 18

A x=−4±3√ 2

B x=2±3√ 2

C x=4±9√ 2

D x=−2±3√2

 $x^2 + 4x + 4 = 18 \\ \\ x^2+4x+4-18= 0 \\ \\ x^2+4x-14=0 \\ \\ x_1_y_2= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} \qquad a= 1\qquad b= 4\qquad c= -14 \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{4^2-4(1)(-14)} }{2(1)} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{16-(-56)} }{2} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{72} }{2} \\ \\ \\ x_1= \dfrac{-4+ \sqrt{72} }{2} \qquad\qquad x_2= \dfrac{-4+ \sqrt{72} }{2}\\ \\ \\ x_1= \dfrac{-4+ \sqrt{2^3*3^2} }{2} \qquad\qquad x_2= \dfrac{-4- \sqrt{2^3*3^2} }{2}$

 $x_1= \dfrac{-4+2*3 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 2*3\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4+6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 6\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4}{2} + \dfrac{6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4}{2}- \dfrac{ 6\sqrt{2} }{2} \\ \\ \\ x_1= -2 + 3 \sqrt{2} \qquad\qquad\quad x_2= -2- 3\sqrt{2} \\ \\ \\ \boxed{x= -2\pm 3\sqrt{2} } \to D)$

7 0

4 years ago

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