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2 years ago

What percent is equivalent to,_, 0.82

1 answer:

3 0

The answer is 82%. To get the percentage, you use the D to P method. In this case, 82 is in the hundredths place so it shows it is a whole number and not a decimal percentage. If it was 0.08, it would be 8%. But if it was 0.435, it would be 43.5%. Basically what you do is move the decimal two times forward to get the percentage. However, if you try to find the decimal of a percentage, you do the same thing just backwards (P to D). Move the decimal two times to the left. Like 82% is 0.82 or 8% turns into 0.08. You get the idea! If it helps just think it was D two P or P two D.

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Find the area of the shaded region.

Gennadij [26K]

Answer:

area = 3.44 in²

Step-by-step explanation:

area of square = 4 x 4 = 16 cm²

area of circle = (3.14)(2²) = 12.56 cm²

area = 16 - 12.56 = 3.44 in²

5 0

2 years ago

Chris earns four times Vesna's wage v and Vesna earns $17 more than Dawn. How many dollars does Chris earn if their combined wag

guajiro [1.7K]

Call Dawn's wage x, we will have Vesna's wage = x + 17 and Chris' wage = 4x(x + 17). So we have the equation:
$x + (x + 17) + 4 \times (x + 17) = 163 \\ 2x + 17 + 4x + 68 = 163 \\ 6x = 78 \\ x = 13$
Therefore, Chris's wage:
$4 \times (13 + 17) = 120$

7 0

3 years ago

The common ratio of a geometric series is \dfrac14 4 1 start fraction, 1, divided by, 4, end fraction and the sum of the first

myrzilka [38]

Answer:

The common ratio of a geometric series is \dfrac14

start fraction, 1, divided by, 4, end fraction and the sum of the first 4 terms is 170

The first term is 128

Step-by-step explanation:

The common ratio of the geometric series is given as:

$r = \frac{1}{4}$

The sum of the first 4 term is 170.

The sum of first n terms of a geometric sequence is given b;

$s_n=\frac{a_1(1-r^n)}{1-r}$

common ratio, n=4 and equate to 170.

$\frac{a_1(1-( \frac{1}{4} )^4)}{1- \frac{1}{4} } = 170$

$\frac{a_1(1- \frac{1}{256} )}{ \frac{3}{4} } = 170\\\\ \frac{255}{256} a_1 = \frac{3}{4} \times 170\\\\\frac{255}{256} a_1 = \frac{255}{2} \\\\\frac{1}{256} a_1 = \frac{1}{2} \\\\ a_1 = \frac{1}{2} \times 256\\\\a_1 = \frac{1}{2} \times 256 \\\\= 128$

8 0

2 years ago

Find the equation of the the line -1/4 that passed through the point (12,-4).

mihalych1998 [28]

Y=mx+c
-4=6(12)+c
-4=72+c
-4-72=c
c=-76
y=mx+c
y=6x-76

3 0

2 years ago

What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?

xxMikexx [17]

We have been given an equation of hyperbola $\frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1$ . We are asked to find the center of hyperbola.

We know that standard equation of a vertical hyperbola is in form $\frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1$ , where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

$\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1$

Now we can see that value of k is $-3$ . Therefore, the vertex of given hyperbola will be at point $(6,-3)$ and option D is the correct choice.

6 0

2 years ago