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Olin [163]
3 years ago
9

The table below shows selected points from a function.

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
6 0

The rate change of interval for the given table is Constant , so the function a linear function.

<u>Step-by-step explanation:</u>

A linear function is defined as a function which yields a line in a graph and the rate of change(constant) is called as slope.

Since the rate is constant, then function will result in a straight line.

From the given table the slope m=1 and it changes constantly.

The linear equation formula is y=mx+c.

where m is the slope and c is the y-intercept.

The linear equation for the given table is y=x+1.

∴ The rate change of interval for the given table is Constant , so the function a linear function.

If the graph for a function has any shapes other than a straight line then it doesn't have a constant slope and it will be a non-linear function.

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Arianna has $0.90 worth of nickels and dimes. She has 4 times as many nickels as
Tanya [424]

Answer:

X=3

Step-by-step explanation:

       0.05(4x) + 0.1x = 0.90

           0.2x + 0.1x = 0.90

                 0.3x = 0.90

                      x = 3

8 0
3 years ago
Plz help me answer and explain this is my first time! :D
noname [10]
864mm2 you multiply to fins SA of 1 them multiply total squares

3 0
3 years ago
Read 2 more answers
Resolver: -4 (2 - 8x) - 3 (7x + 2) = 4x - 4 + x + 8
allsm [11]

Answer:

The chosen topic is not meant for use with this type of problem. Try the examples below.

2x+1 ,  3x+9

x3+x2+1 ,  x2+2x−6

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Step-by-step explanation:

hope this helps

3 0
3 years ago
A researcher wants to check the claim that convicted burglars spend less than 18.7 months in jail, on average. She takes a rando
vivado [14]

Answer:

a. No, there is not enough evidence to support the claim using a level of significance of 1%.

b. Null Hypothesis, H_0 : \mu \geq 18.7 months  

c. Alternate Hypothesis<u>,</u> H_A : \mu < 18.7 months

d. P-value of hypothesis test = 0.0199 or 1.99%

e. We conclude that the convicted burglars spend more than or equal to 18.7 months in jail, on average.

Step-by-step explanation:

We are given that a researcher wants to check the claim that convicted burglars spend less than 18.7 months in jail, on average.

She takes a random sample of 67 such cases from court files and finds that the mean is 16.8 months with a standard deviation of 7.3 months.

<em><u>Let </u></em>\mu<em><u> = true mean time convicted burglars spend in jail.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \geq 18.7 months   {means that the convicted burglars spend more than or equal to 18.7 months in jail, on average}

<u>Alternate Hypothesis,</u> H_A : \mu < 18.7 months   {means that the convicted burglars spend less than 18.7 months in jail, on average}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean time spent in jail = 16.8 months

             s = sample standard deviation = 7.3 months

             n = sample of cases = 67

So, <em><u>test statistics</u></em>  =   \frac{16.8-18.7}{\frac{7.3}{\sqrt{67} } }  ~ t_6_6

                               =  -2.13

Hence, the value of test statistics is -2.13.

<u>Now, P-value of the test statistics is given by;</u>

      P-value = P( t_6_6 < -2.13) = 0.0199 or 1.99%

  • If the P-value of test statistics is more than the level of significance, then we will not reject our null hypothesis as it will not fall in the rejection region.
  • If the P-value of test statistics is less than the level of significance, then we will reject our null hypothesis as it will fall in the rejection region.

<em>Now, here the P-value is 0.0199 or 1.99% which is clearly higher than the level of significance of 1%, so we will not reject our null hypothesis as it will not fall in the rejection region.</em>

Therefore, we conclude that the convicted burglars spend more than or equal to 18.7 months in jail, on average.

6 0
3 years ago
If the profit of Tk.x in 4 years at the rate of x% is Tk.x, then what is the value of x?
I am Lyosha [343]

Answer:

x = 25

Step-by-step explanation:

Given:

Amount invest p = Tk.x

Number of year t = 4

Rate r = x%

Profit = Tk.x

Find:

Value of x

Computation:

Profit = prt / 100

Tk.x = [(Tk.x)(x)(4)] / 100

x = 100 / 4

x = 25

3 0
3 years ago
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