Question

Find the surface area of the triangular prism below

Answer 1

QUESTION: To find the surface area of the triangular Prism given in the figure.

ANSWER:

$Area \: of \: Prism = 136 \: {units}^{2}$

STEP BY STEP EXPLANATION:

In a triangular Prism there are three rectangular faces and two triangular faces

As, in the given question the prism is irregular. So, it have different area of base rectangular face than that of the two side rectangular faces.

A/C to the question,

Base of triangular face = 6 unit

Height of triangular face = 4 unit

Length of side rectangular face = 7 unit

Breadth of side rectangular face = 5 unit

Length of base rectangular face = 7 unit

Breadth of base rectangular face = 6 unit

Area of triangle = $\frac{1}{2} \times base \times height$

Area of rectangle = Length × Breadth

AREA OF PRISM = 2 × AREA OF TRIANGULAR FACE + 2 × AREA OF SIDE RECTANGULAR FACE + AREA OF BASE RECTANGULAR FACE

=> Area of Prism = $2(\frac{1}{2} \times Base \: of \: triangular \: face \times Height \: of \: triangular \: face)$ + 2(Length of side rectangular face × Breadth of side rectangular face) + Length of base rectangular face × Breadth of base rectangular face

=> Area of Prism = $2( \frac{1}{2} \times 6 \times 4)$ + 2(7 × 5) + 7 × 5

=> Area of Prism = 2(3 × 4) + 2(7 × 5) + 7 × 6

=> Area of Prism = 2(12) + 2(35) + 42

=> Area of Prism = 24 + 70 + 42

=> Area of Prism = 136 units²