PLEASE HELP!!!!

Divide the Polynomials

Tema [17]

1. 2a^2+4a-5

2. 6t^3-t^2-2t-1

3. 2y^2-3y+1

8 0

4 years ago

What is the value of y ?

Finger [1]

Answer:

67

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Robert plays cricket. He hit the ball in such a way that it goes up 180 feet

PilotLPTM [1.2K]

Answer:

4 feet per second

Step-by-step explanation:

Hi there!

$v=D/t$ where v is velocity (speed), D is distance and t is time

Plug in the known values (D=180 feet, t=45 seconds)

$v=180/45\\v=4$

Therefore, the speed of the ball is 4 feet per second.

I hope this helps!

4 0

3 years ago

Read 2 more answers

We are standing on the top of a 1680 ft tall building and throw a small object upwards. At every second, we measure the distance

MAVERICK [17]

Answer:

a) The height of the small object 3 seconds after being launched is 2304 feet.

b) The small object ascends 128 feet between 5 seconds and 7 seconds.

c) The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) The object will take 21 seconds to hit the ground.

Step-by-step explanation:

The correct formula for the height of the small object is:

$h(t) = -16\cdot t^{2}+256\cdot t+1680$ (1)

Where:

$h$ - Height above the ground, measured in feet.

$t$ - Time, measured in seconds.

a) The height of the small object at given time is found by evaluating the function:

$h(3\,s)= -16\cdot (3\,s)^{2}+256\cdot (3\,s)+1680$

$h(3\,s) = 2304\,ft$

The height of the small object 3 seconds after being launched is 2304 feet.

b) First, we evaluate the function at $t = 5\,s$ and $t = 7\,s$ :

$h(5\,s)= -16\cdot (5\,s)^{2}+256\cdot (5\,s)+1680$

$h(5\,s) = 2560\,s$

$h(7\,s)= -16\cdot (7\,s)^{2}+256\cdot (7\,s)+1680$

$h(7\,s) = 2688\,s$

We notice that the small object ascends in the given interval.

$\Delta h = h(7\,s)-h(5\,s)$

$\Delta h = 128\,ft$

The small object ascends 128 feet between 5 seconds and 7 seconds.

c) If we know that $h = 2640\,ft$ , then (1) is reduced into this second-order polynomial:

$-16\cdot t^{2}+256\cdot t-960=0$ (2)

All roots of the resulting equation come from the Quadratic Formula:

$t_{1} = 10\,s$ and $t_{2}= 6\,s$

The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) If we know that $h = 0\,ft$ , then (1) is reduced into this second-order polynomial:

$-16\cdot t^{2}+256\cdot t +1680 = 0$ (3)

All roots of the resulting equation come from the Quadratic Formula:

$t_{1} = 21\,s$ and $t_{2} = -5\,s$

Just the first root offers a solution that is physically reasonable.

The object will take 21 seconds to hit the ground.

8 0

3 years ago

Help me please!!!!!!!!

Romashka [77]

Answer:

y = -6x - 5

Step-by-step explanation:

To find the equation using the point-slope equation, we need the slope and the y-intercept of the line

Finding the slope of the line:

We will calculate the slope between these 2 points: (-1 , 1) and (0 , -5)

Slope = Rise / Run

Rise of the line = y1 - y2

Rise = 1 - (-5)

Rise = 1 + 5

Rise = 6

Run of the line = x1 - x2

Run = -1 - 0

Run = -1

Slope of the line:

Slope = Rise / Run

Slope = 6 / -1

Slope = -6

Finding the y-intercept:

y-intercept of a line is the y-ordinate of the point where the line intersect the y-axis

From the graph, we can see that the line intersects the y-axis at (0 , -5)

y-coordinate of the point = -5

y-intercept = -5

Equation of the line:

This is the general formula of the slope-intercept:

y = mx + b (where m is the slope of the line and b is the y-intercept )

Replacing the variables

y = (-6)x + (-5)

y = -6x - 5

4 0

3 years ago