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murzikaleks [220]

3 years ago

9

On the last day of a Shakespeare class, an English teacher asked her students which play they liked most. Out of the 18 students

who have submitted responses so far, 6 liked Much Ado About Nothing best. What is the experimental probability that the next student to respond likes Much Ado About Nothing best?
Write your answer as a fraction or whole number.

1 answer:

Vika [28.1K]3 years ago

7 0

Answer:

1/3

Step-by-step explanation:

There were 18 students and six liked Much Ado About Nothing. So, you could write this as 6/18 which simplifies to 1/3.

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How do I find the value of the variable?

Kryger [21]

93+36+m=180 combine like terms
93+36=129 rewrite
129+m=180 subtract 129 from both sides
180-129=51 rewrite
M=51 and to check this just plug 51 in for m
93+36+51=180
93+36=129
129+51=180
180=180
Hope this helps have a nice nite!

3 0

4 years ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

Answer ? I need helpppppp

emmainna [20.7K]

Answer:

1/3138428376721

or

3.18630817 * 10^-13

The answer is A

3 0

3 years ago

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Maine has a cold climate in the winter. Which statement about the probability of temperatures falling below 32 Fahrenheit in Mai

aliya0001 [1]

Answer: The probability is 100.

Step-by-step explanation:

Maine has a cold climate in winter which means that we can expect cold weather when winter season reaches Maine.

January is a winter month so the probability that the temperature in Maine will drop below 32° in January is a certain occurrence which means that the probability is a 100%.

6 0

3 years ago

The ampitude/frequency/period of y=1/4cos1/2x is 4 pie

Fantom [35]

Amplitude: 1/4 (= |a|)
Frequency: 1/2 (= |b|)
Period: 4pi (= 2pi/|b|)

7 0

4 years ago