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Bingel [31]
3 years ago
13

MAX POINTS. Brainliest for the best answer. Please explain your answer as well.

Mathematics
2 answers:
disa [49]3 years ago
4 0

Answer:

Graphs A and C

Step-by-step explanation:

  1. Line s : y = 1/3x - 3
  • for x = 0 → y = 1/3(0) - 3 = 0 - 3 = -3

then the line passes through the point (0,-3)

  • for x = 9 → y = 1/3(9) - 3 = 3 - 3 = 0

then the line passes through the point (9,0)

and according to the picture ,only in graphs A and C the line C passes through (0,-3) and (9,0)

so the graph solution is either graph A or graph C.

   2. line t : y = -x + 5

  • for x = 0 → y = -(0) + 5 = 0 + 5 = 5

then the line passes through the point (0,5)

  • for x = 5 → y = -(5) + 5 = 0

then the line passes through the point (5,0)

and according to the picture ,only in graphs A and C the line C passes through (0,5) and (5,0).

<u>conclusion:</u>

both graph A and C represent correctly show Lines s and t and the point P

<em><u>Remark :</u></em> if you look closely to the graphs A and C ,they are the same thing.

Alenkinab [10]3 years ago
4 0

Answer: Graphs A and C

Step-by-step explanation:

Line s : y = 1/3x - 3

for x = 0 → y = 1/3(0) - 3 = 0 - 3 = -3

then the line passes through the point (0,-3)

for x = 9 → y = 1/3(9) - 3 = 3 - 3 = 0

then the line passes through the point (9,0)

and according to the picture ,only in graphs A and C the line C passes through (0,-3) and (9,0)

so the graph solution is either graph A or graph C.

  2. line t : y = -x + 5

for x = 0 → y = -(0) + 5 = 0 + 5 = 5

then the line passes through the point (0,5)

for x = 5 → y = -(5) + 5 = 0

then the line passes through the point (5,0)

and according to the picture ,only in graphs A and C the line C passes through (0,5) and (5,0).

conclusion:

both graph A and C represent correctly show Lines s and t and the point P

Remark : if you look closely to the graphs A and C ,they are the same thing.

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Answer:

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The random variable <em>X</em> can be defined as the number of guests until the next one pays by American Express credit card

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E(X)=\frac{1-p}{p}

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(b)

Compute the probability that the first guest to use an American Express is within the first 10 to checkout as follows:

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Thus, the probability that the first guest to use an American Express is within the first 10 to checkout is 0.0215.

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