T1 = 3
t2 = 2*t1 = 6
t3 = 2*t2 = 12
t4 = 24
t5 = 48
Hello,
To solve we need to factor y^2-2y-35:
(y-7)(y+5)=0
Now solve for :
(When will (y-7)(y+5)equal zero?)
When y-7=0 or y+5=0
Solve for the 2 equations above and;
y= 7,-5
Hope this helps, have a great day!
Answer:
Yes
Step-by-step explanation:
1 hour = 60 min
25 hours = 60 x 25 min
Answer:
lol same
Step-by-step explanation: