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3 years ago

60 is 20% of what number?

Mathematics

2 answers:

ddd [48]3 years ago

6 0

Answer:

300

Step-by-step explanation:

if 20% is 60 then try to find the 100% by multiplying

20% = 60

100% = x

100 × 60 = 20x

x = 300

AfilCa [17]3 years ago

6 0

Answer: 300

Step-by-step explanation: 20% is 1/5th of 100%. Multiply 60x5=300

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3 years ago

The probability Brenda will recieve a telemarketing call is 15%. If she gets 20 calls a day, how many can she expect to be telem

Arturiano [62]

Answer:

3 telemarketing calls

Step-by-step explanation:

First convert 15% to a decimal:

.15

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Build an expression

x(.15)

substitute our value for x (20 calls)

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3 years ago

What is the answer to this question?

geniusboy [140]

Answer:

A-75 and B-25

Step-by-step explanation:

Firstly, divide the 200 students by the amount of sections (8) and that gives you 25 a section. Since year 7 has 3 sections and year 9 has 1, 3(25)=75 and 25(1)=25.

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3 years ago

Read 2 more answers

A baseball is dropped from a glider 500 feet above the ground. The height (in feet) above the ground is modeled by the function

Sophie [7]

A) 436 ft

B) t = 5 sec

C) 5.60 s

Step-by-step explanation:

The height of the ball at time t is given by the equation

$h(t)=-16t^2+500$

where

$-16 ft/s^2$ is the acceleration of the ball (acceleration of gravity, downward)

+500 is the initial height of the ball, at time t = 0

Here we want to find the height of the ball after 2 seconds, so at a time of

t = 2 s

Substituting into the equation, we find:

$h(2)=-16\cdot 2^2+500=436 ft$

Here we want to find the time it takes for the ball to fall to a height of 100 feet above the ground, so the time t at which

h(t) = 100 ft

As stated in the text of the question, the height of the ball at time t is given by

$h(t)=-16t^2+500$

Since

h(t) = 100, we have

$100=-16t^2+500$

And solving for t we find:

$16t^2=400\\t^2=25\\t=\pm 5$

So, the correct solution is the positive one:

t = 5 sec

The ball reaches the ground when the height of the ball has became zero:

$h(t) = 0$

The height of the ball at time t is given by

$h(t)=-16t^2+500$

And substituting

h(t) = 0

We get

$0=-16t^2+500$

And solving the equation for t, we find the time t at which the ball reaches the ground:

$16t^2=500\\t^2=31.25\\t=\pm 5.6 s$

So, the correct solution is the positive one:

t = 5.60 s

3 0

4 years ago