<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2x%20%2B%203%20%20%7D%20%20-%20%20%5Csqrt%7Bx%20-%202%7D%20%20%3D%202%20" id="Tex

3 years ago

Formula1" title=" \sqrt{2x + 3 } - \sqrt{x - 2} = 2 " alt=" \sqrt{2x + 3 } - \sqrt{x - 2} = 2 " align="absmiddle" class="latex-formula">
find x

Mathematics

1 answer:

emmainna [20.7K]3 years ago

8 0

Answer:

Step-by-step explanation:

hello : here is an solution

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if f(x)=2(x)^2+5sqrt(x+2), complete the follwoing statement ( round your answer to the nearest hundreth) : f(0)=_____

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Answer:

$f(0)=7.07$

Step-by-step explanation:

We have the function $f(x)=2(x)^2+5\sqrt{(x+2)}$

In this case we want to find the value of f0)

To find f(0) you must replace the x in the function with the number 0 and solve as shown below

$f(0)=2(0)^2+5\sqrt{(0+2)}$

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