F(1) = 1 f(2) = 2 f(n) = f(n − 2) + f(n - 1) f(3) =?
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Answer:
Step-by-step explanation:
Let X be the no of defective components produced by a certain process in one day
X is Poisson with parameter = 20
Y = no of components that can be repaired
Since each component to be repaired is independent of the other Y is Binomial with p =0.60
a)
b) P(Y = 10)= Binomial prob (15,0.6) for y =10
=
Here no of repairables X is binomial.
c) Prob for 15 produced and 10 repairable = product of a and b
= 0.009603
Final value = Initial value × (mutiplier)^n
We have;
Initial value = 9300
Multiplier = 100%+3.2% = 103.2% = 1.032
Number of quarters in a year = 4
Substitute all values into the formula, we have
rounded to two dp
We have;
Initial value = 9300
Multiplier = 100%+3.2% = 103.2% = 1.032
Number of quarters in a year = 4
Substitute all values into the formula, we have