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Mnenie [13.5K]
3 years ago
5

Please help me with this question.

Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0

Answer:

bottom left corner

Step-by-step explanation:

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Hello, first of all we can find a value for f(1)

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(uv)'=u'v+uv' \text{ and } \dfrac{df(x^2)}{dx}=2xf'(x^2) \text{ so we can write}\\\\f(x)+xf'(x)+2xf'(x^2)=0\\\\\text{And then, for x = 1}\\\\f(1)+f'(1)+2f'(1)=0\\\\ f(1)+3f'(1)=0\\\\ 3f'(1)=-f(1)=-1\\\\\large \boxed{ f'(1)=-\dfrac{1}{3} }

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3 years ago
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2 years ago
LITERAL EQUATIONS: A literal equation is one consisting of all letters (or at least mostly letters). The Latin word literalis me
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