At which values of x does the function F(x) have a vertical asymptote? Check
1 answer:
Answer:
B, C and F
Step-by-step explanation:
Given
f(x) =
The denominator of f(x) cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.
solve
2x(x + 3)(x - 9) = 0
Equate each factor to zero and solve for x
2x = 0 ⇒ x = 0 → C
x + 3 = 0 ⇒ x = - 3 → B
x - 9 = 0 ⇒ x = 9 → F
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Option A is correct. The range of the function given above expressed as an interval notation is (–∞, ∞)
Given the function
- We are to find the range of the function.
- First, we can see that the value of x² inside the square root will always be a positive value no matter the domain values of x.
- Since the input value exists on all real numbers, hence<em> the output values will also exist on all real numbers since the </em><em>range</em><em> is dependent on the values of the </em><em>domain.</em>
Hence the range of the function given above expressed as an interval notation is (–∞, ∞)
Learn more here: brainly.com/question/16724504
Answer:
2243x32
Step-by-step explanation:
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