Question

At which values of x does the function F(x) have a vertical asymptote? Check

Answer 1

Answer:

B, C and F

Step-by-step explanation:

Given

f(x) = $\frac{7}{2x(x+3)(x-9)}$

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.

solve

2x(x + 3)(x - 9) = 0

Equate each factor to zero and solve for x

2x = 0 ⇒ x = 0 → C

x + 3 = 0 ⇒ x = - 3 → B

x - 9 = 0 ⇒ x = 9 → F