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algol13
3 years ago
9

At which values of x does the function F(x) have a vertical asymptote? Check

Mathematics
1 answer:
Soloha48 [4]3 years ago
3 0

Answer:

B, C and F

Step-by-step explanation:

Given

f(x) = \frac{7}{2x(x+3)(x-9)}

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.

solve

2x(x + 3)(x - 9) = 0

Equate each factor to zero and solve for x

2x = 0 ⇒ x = 0 → C

x + 3 = 0 ⇒ x = - 3 → B

x - 9 = 0 ⇒ x = 9 → F

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SIZIF [17.4K]

Answer:

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3 0
3 years ago
WORTH 60 POINTS! PLZ HELP! BRAINLIEST OPPORTUNITY!
makkiz [27]

Answer:

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<u>-3(x - 4) + 5 = -x - 3</u>

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<em>+3x          +3x</em>

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<em>+3        + 3</em>

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<u />

I hope that this helps! :)

5 0
3 years ago
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Trava [24]
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3 years ago
Read 2 more answers
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