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2 years ago

What is the equation of a line with a slope of -2 that passes through the point (6, 8)?

Mathematics

2 answers:

elena-14-01-66 [18.8K]2 years ago

4 0

Answer:

2x+y = 20

Step-by-step explanation:

The equation for a line is y = mx+b where m is the lope and b is the y intercept

y = -2x+b

substitute the point into x and y

8 = -2(6) +b

8 = -12+b

Add 12 to each side

20 =b

y = -2x+20

Add 2x to each side

2x+y = 20

KIM [24]2 years ago

3 0

Answer: 2x+y = 20

Step-by-step explanation:

The equation for a line is y = mx+b where m is the lope and b is the y intercept

y = -2x+b

substitute the point into x and y

8 = -2(6) +b

8 = -12+b

Add 12 to each side

20 =b

y = -2x+20

Add 2x to each side

2x+y = 20

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What is the product or properties of 8*51 how do i do this

Dovator [93]

The answer is 408. One way to solve is to do 8*50 and then do 8*1 and add the products together.

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2 years ago

50 POINTS!!! Plz show work questions are in the addon

emmasim [6.3K]

1. Each term in this polynomial has a common factor of $3x^3$ :

$12x^6-9x^4+18x^3=3x^3(4x^3-3x+6)$

2. Not sure what the "vertical method" is, but I would guess it refers to some way of visualizing the distributive property.

$(3x-5)(2x^2+7x-3)=3x(2x^2+7x-3)-5(2x^2+7x-3)$

$(3x-5)(2x^2+7x-3)=(6x^3+21x^2-9x)+(-10x^2-35x+15)$

$(3x-5)(2x^2+7x-3)=6x^3+11x^2-44x+15$

3. You can use the same approach as in (2), or recall that $(a+b)^2=a^2+2ab+b^2$ :

$(5x-4y)^2=(5x)^2+2(5x)(-4y)+(-4y)^2$

$(5x-4y)^2=25x^2-40xy+16y^2$

4. Recall that a difference of squares can be factored as $a^2-b^2=(a-b)(a+b)$ . So

$(2x^2-7)(2x^2+7)=(2x^2)^2-7^2$

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2 years ago

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2 years ago

The yellow boxes on the bottom are the answers. Please help TYSM

sveticcg [70]

Answer:

$1.\ 8p = 64, p =8$

$2. -\dfrac{w}{4} = 8, w = -32$

$3. -5c = -20, c =4$

$4.\ 9m=45, m = 5$

$5. \dfrac{b}{25} = -3, b =-75$

$6. \dfrac{d}{-2} = 20, d=-40$

Step-by-step explanation:

Now let us see the detailed solution of each part:

Part 1:

$8p -15 = 49\\\Rightarrow 8p =49+15\\\Rightarrow 8p = 64\\\Rightarrow p =8$

Part 2:

$\dfrac{-w}{4}+18=26\\\Rightarrow \dfrac{-w}{4} = 26-18\\\Rightarrow \dfrac{-w}{4} = 8\\\Rightarrow -w = 8 \times 4\\\Rightarrow w =-32$

Part 3:

$-5c-15=-35\\\Rightarrow -5c = -35 +15\\\Rightarrow -5c = -20\\\Rightarrow c = 4$

Part 4:

$9m +10=55\\\Rightarrow 9m =55-10\\\Rightarrow 9m =45\\\Rightarrow m =5$

Part 5:

$\dfrac{b}{25}-83=-86\\\Rightarrow \dfrac{b}{25} = -86 +83\\\Rightarrow \dfrac{b}{25} = -3\\\Rightarrow b = -75$

Part 6:

$\dfrac{d}{-2}+85=105\\\Rightarrow \dfrac{d}{-2} = 105-85\\\Rightarrow \dfrac{d}{-2} = 20\\\Rightarrow d=20 \times -2\\\Rightarrow d =-40$

Please refer to attached image for the answers.

7 0

2 years ago

Angle 1 and angle 2 form a linear pair. The measure of angle 2 is six more than twice the measure of angle 1. Find m angle 2

Mekhanik [1.2K]

Since the given problem states that the two angles, angle 1 and angle 2 form a linear pair, this means that they form a 180° line, so that:

measure angle 1 + measure angle 2 = 180°

Since measure of angle 2 is six more than twice the measure of angle 1, therefore:

measure angle 2 = 2 (measure angle 1) + 6

hence, substituting this into the first equation:

measure angle 1 + 2 (measure angle 1) + 6 = 180

3 (measure angle 1) = 174

measure angle 1 = 58°

Therefore,

measure angle 2 = 2 (measure angle 1) + 6

measure angle 2 = 2 (58°) + 6

<span>measure angle 2 = 122°</span>

6 0

2 years ago