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3 years ago

Parallel lines s and t are cut by a transversal r.

Mathematics

2 answers:

MAVERICK [17]3 years ago

8 0

Answer:

Angles 2 and 8.

Step-by-step explanation:

Alternate exterior angles are two angles that have the same measurement but are on the outside of a pair of lines.

The pair 2 and 8 fits these requirements.

Hope this helps!

Eduardwww [97]3 years ago

5 0

Answer:

Step-by-step explanation:

I did the quiz on Edg

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Please prove this........

Crazy boy [7]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

7 0

3 years ago

CORRECT ANSWER WILL GET BRAINEST (50 points)

Katarina [22]

Answer:

Pedro had 1,479 base hits and Ricky had 1,200 base hits :)

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

What is the rate of change for f(x) =7 sin x-1 on the interval from x=0 to x=piover 2

Oksi-84 [34.3K]

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------$

$\bf f(x)= 7sin(x)-1 \qquad 
\begin{cases}
x_1=0\\
x_2=\frac{\pi }{2}
\end{cases}\implies \cfrac{f\left( \frac{\pi }{2} \right)-f(0)}{\frac{\pi }{2}-0}
\\\\\\
\cfrac{[7\cdot 1-1]~-~[7\cdot 0-1]}{\frac{\pi }{2}}\implies \cfrac{6-(-1)}{\frac{\pi }{2}}\implies \cfrac{6+1}{\frac{\pi }{2}}\implies \cfrac{7}{\frac{\pi }{2}}\implies \cfrac{14}{\pi }$

7 0

3 years ago

Why does it take 10 copies of 1/6 to make the same amount of 5 copies of 1/3?

irakobra [83]

10 of 1/6 (10 times 1/6) is 1 4/65 or 1 2/3 simplified. 5 of 1/3 (5 times 1/3) is
1 2/3

8 0

3 years ago

Derivative of square root 24x

Andrews [41]

Think of it as (24x)^1/2 then use chain rule. Which means first derive (24x)^1/2 as deriving u^1/2 (substitute u for 24x), then deriving 24x, finally write those 2 derivatives as a multiplication (as in a*b).

3 0

3 years ago

Read 2 more answers