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Studentka2010 [4]
3 years ago
14

Parallel lines s and t are cut by a transversal r.

Mathematics
2 answers:
MAVERICK [17]3 years ago
8 0

Answer:

Angles 2 and 8.

Step-by-step explanation:

Alternate exterior angles are two angles that have the same measurement but are on the outside of a pair of lines.

The pair 2 and 8 fits these requirements.

Hope this helps!

Eduardwww [97]3 years ago
5 0

Answer:

C

Step-by-step explanation:

I did the quiz on Edg

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How many solutions does this problem have <br> Y=-2x -4<br> Y= 3x plus 3
S_A_V [24]

Answer:

There is one possible solution

Step-by-step explanation:

Here, we want to get the number of solutions

We can proceed to solve the equation

we have two y values so we can directly equate the x parts

-2x - 4 = 3x + 3

3x + 2x = -3-4

5x = -7

x = -7/5

To get y, we substitute

We can only get one value of y too

So we have a point (x,y) as the solution to the system of equations

7 0
2 years ago
Help its due tmmr and i dont under stand
const2013 [10]

If we want rice per person, that's

\dfrac{25}{3}

1a. Answer: 25/3

That's between 24/3 and 27/3 i.e. between

1b. Answer: 8 and 9


6 0
3 years ago
Read 2 more answers
What is 2/3 of the product of 3/8and 16
MA_775_DIABLO [31]

Answer:

4

Step-by-step explanation:

First, multiply 3/8 x 16:

3/8 x 16 = 6

Then find 2/3 of 6:

6/3=2

2x2=4

3 0
3 years ago
Read 2 more answers
. For each of these intervals, list all its elements or explain why it is empty. a) [a, a] b) [a, a) c) (a, a] d) (a, a) e) (a,
Eva8 [605]

Answer:

Elements are of the form

 (i) [a,a]=\{[x,y] : a\leq x\leq a, a\leq y\leq a; a\in \mathbb R\}

(ii) [a,b)=\{[x,y) :a\leq x

(iii)(a,a]=\{(x,y] :a

(iv)(a,a)=\{(x,y): a

(v) (a,b) where a>b=\{(x,y) : a>x>b,a>y>b;a>b,a,b \in \mathbb R\}

(vi) [a,b] where a>b=\{[x,y] : a\geq x\geq b,a\geq y\geq b;a>b,a,b \in \mathbb R\}

Step-by-step explanation:

Given intervals are,

(i) [a,a] (ii) [a,a) (iii) (a,a] (iv) (a,a) (v) (a,b) where a>b (vi)  [a,b] where a>b.

To show all its elements,

(i) [a,a]

Imply the set including aa from left as well as right side.

Its elements are of the form.

\{[a,a] : a\in \mathbb R\}=\{[0,0],[1, 1],[-1,-1],[2,2],[-2,-2],[3,3],[-3,-3],........\}

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a] represents singleton sets, and singleton sets are empty so is [a,a].

(ii) [a,a)

This means given interval containing a by left and exclude a by right.

Its elements are of the form.

[ 1, 1),[-1,-1),[2,2),[-2,-2),[3,3),[-3,-3),........

Since there is a singleton element a of real numbers withis the set, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a) represents singleton sets, and singleton sets are empty so is [a.a).

(iii) (a,a]

It means the interval not taking a by left and include a by right.

Its elements are of the form.

( 1, 1],(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  (a,a] represents singleton sets, and singleton sets are empty so is (a,a].

(iv) (a,a)

Means given set excluding a by left as well as right.

Since there is a singleton element a of real numbers, this set is empty.

Its elements are of the form.

( 1, 1),(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Because there is no increment so if a\in \mathbb R then the set  (a,a) represents singleton sets, and singleton sets are empty, so is (a,a).

(v) (a,b) where a>b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which not take x and y by any side of the interval.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

(a,b)=\{(5,0),(5,1),(5,2).....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

(vi) [a,b] where a\leq b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which include both x and y.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

[a,b]=\{[5,0],[5,1],[5,2].....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

8 0
3 years ago
Which type of question is most useful in a group discussion?
polet [3.4K]

Answer:

B

Step-by-step explanation:

it is B I am so sorry if it is wrong

3 0
2 years ago
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