If you type the equation on math way it will show you a graph for your answer!
Answer:
Step-by-step explanation:
There are 1000 m in 1 km, and 3600 s in 1 h, so the speed conversion is ...
![\dfrac{25\,m}{s}\cdot\dfrac{1\,km}{1000\,m}\cdot\dfrac{3600\,s}{1\,h}=\dfrac{90\,km}{h}](https://tex.z-dn.net/?f=%5Cdfrac%7B25%5C%2Cm%7D%7Bs%7D%5Ccdot%5Cdfrac%7B1%5C%2Ckm%7D%7B1000%5C%2Cm%7D%5Ccdot%5Cdfrac%7B3600%5C%2Cs%7D%7B1%5C%2Ch%7D%3D%5Cdfrac%7B90%5C%2Ckm%7D%7Bh%7D)
The car's speed is 90 km/h.
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In 2 hours, the car will travel ...
distance = speed · time = (90 km/h)(2 h) = 180 km
X - (-20) = 5
When you subtract a negative, change it to addition:
X + 20 = 5
Subtract 20 from both sides:
X = -15
Write the equation of the first train: x = 12t
Write the equation of the second train: y = -20t+72, assuming the train one is at the origins when t = 0.
Now solve the equation: 12t=-20t+72,
32t = 72, then t = 2.25 hours. The two train meet after 2.25 hours.
Now the equation of the <span>pigeon is like this: x = 48t.
</span>Then for t = 2.25, we get
![x=2.25\times48=108 km](https://tex.z-dn.net/?f=x%3D2.25%5Ctimes48%3D108%20km)
<span>
The Hyde has flown 108 km when the trains meet.</span>