Answer:
the answer is number 3)2
Step-by-step explanation:
subtract the both
The largest possible volume of the given box is; 96.28 ft³
<h3>How to maximize volume of a box?</h3>
Let b be the length and the width of the base (length and width are the same since the base is square).
Let h be the height of the box.
The surface area of the box is;
S = b² + 4bh
We are given S = 100 ft². Thus;
b² + 4bh = 100
h = (100 - b²)/4b
Volume of the box in terms of b will be;
V(b) = b²h = b² * (100 - b²)/4b
V(b) = 25b - b³/4
The volume is maximum when dV/db = 0. Thus;
dV/db = 25 - 3b²/4
25 - 3b²/4 = 0
√(100/3) = b
b = 5.77 ft
Thus;
h = (100 - (√(100/3)²)/4(5.77)
h = 2.8885 ft
Thus;
Largest volume = [√(100/3)]² * 2.8885
Largest Volume = 96.28 ft³
Read more about Maximizing Volume at; brainly.com/question/1869299
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The answer is B. -7m+12.
First distribute the -2 to 6m and -5.
5m-2(6m-5)+2
5m+(-2*6m)+(-2*-5)+2
5m+-12m+10+2
After that, combine the like terms.
5m+-12m+10+2
-5m+-12m=-7m
10+2=12
The simplified expression is -7m+12.
Answer:
B.0.31
Step-by-step explanation:
% of change = amount of change/original price
R=(P-D)÷P
39-27=12
12÷39=.307
≈.31
