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3 years ago

Complete the following statement with the number that makes it true.

Mathematics

1 answer:

Step2247 [10]3 years ago

8 0

Answer: 1000

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kilogram, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38 ... 1 kg = 1000 grams.

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The correct answer is x^np (1-p)^n-1

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What is the common factor of 10 15and 35

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3 years ago

David pays $335 in advance on his account at the gym. Each time he visits the gym , $6 is deducted from the account. Write an eq

Korolek [52]

Answer:

x = 335 - (6 * v)

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3 years ago

A basketball team took a total of 100 shots. One player took 70% of all 100 shots, and

NemiM [27]

The player took a total of 70 shots and missed about 28 shots.

<h3>Percentage</h3>

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Find out more on Percentage at: brainly.com/question/24304697

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2 years ago

Read 2 more answers

Compare the process of solving |x – 1| + 1 < 15 to that of solving |x – 1| + 1 > 15. Check all of the following you includ

zepelin [54]

The required Comparison of the inequalities are

The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.

The range of values encompassing the region's junction is (-13, 15).

If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.

<h3>What is inequality?</h3>

When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.

We take into account the various variables of the inequality

|x – 1| + 1 > 15

Therefore

|-x-1|+1-1<15-1

|-x-1|-1 <14

13<x<15

The required region lies between the inequality -13 <x< 15.

Simplify the inequality Ix-11+1 > 15 we get,

|x-1|+1 > 15

|x+1| +1-1 >15-1

|x-1| > 14

x> 15

x<-13

If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.

If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.