Answer:
The amount invested at 9% is $93000
The amount invested at 10% is $303000
Step-by-step explanation:
Let the amount invested at 9% interest rate be x
And the amount invested at 10% rate be y
Simple Interest from x in a year = 0.09x
Simple Interest from y in a year = 0.1y
But y = 24000 + 3x
And the sun of the interests, 0.09x + 0.1y = 38670
Now we have a simultaneous eqn
y = 24000 + 3x (eqn 1)
0.09x + 0.1y = 38670 (eqn)
Substitute y into eqn 2
0.09x + 0.1(24000 + 3x) = 38670
0.09x + 2400 + 0.3x = 38670
0.39x = 38670 - 2400
x = 36270/0.39 = $93000
y = 24000 + 3x = 24000 + 3 × 93000 = $303000
Answer:
Step-by-step explanation:
You are right ! It is 8.246 and so on ;)
First you need to find the common denominator. both 6 and 7 go in to 42 evenly
multiply 5/6 by 7 to get 35/42
multiply 2/7 by 6 to get 12/42
subtract 12 from 35 to get 23
23/42
Answer:
Part A:
C= cash Sue earns
H = hours Sue works
C is dependent upon H because C only changes when H is changed.
Part B:
(0,0)
(1,6)
Part C:
C=6H
