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4 years ago

Divide , round to the nearest tenth 336.752 divided by 31

Mathematics

2 answers:

Alika [10]4 years ago

7 0

It is originally 10.829677419 so rounding to the nearest tenth would be 10.9

nirvana33 [79]4 years ago

4 0

Answer:

Round to the nearest tenth 336.752 divided by 31 is 10.9

Step-by-step explanation:

Consider the provided information.

336.752 divided by 31

This can be written as:

336.752 ÷ 31

Divide the number as shown:

$\frac{336.752}{31}$

$10.862968$

Now we need to round it to the nearest tenth.

According to the place value:

Tens Ones Decimal point Tenths Hundredths

10 1 . 0.1 0.01

According to place value tenths place is just after the decimal point so round the number to just after decimal point.

The rule of rounding a number is:

If 0, 1, 2, 3, or 4 follow the number, then no need to change the rounding digit.

If 5, 6, 7, 8, or 9 follow the number, round it up by one number.

Here, the number at the hundredths place is 6 so round it up.

Thus, the round to the nearest tenth is 10.9

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Which M.A.D (mean absolute deviation) would show the most variability

Gwar [14]

Pretty sure it’s 1??

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3 years ago

Graph the hyperbola with equation quantity x minus 1 squared divided by 49 minus the quantity of y plus 3 squared divided by 9 e

Sliva [168]

Answer:

See attached diagram

Step-by-step explanation:

You are given the equation of hyperbola

$\dfrac{(x-1)^2}{49}-\dfrac{(y+3)^2}{9}=1$

From this equation,

the center of hyperbola is at point (1,-3);
the real semi-axes $a^2=49\Rightarrow a=7;$
the imaginary semi-axes $b^2=9\Rightarrow b=3.$

Draw two parallel lines x=1 and y=-3 (they intersect at the center of hyperbola), then on horizontal line match two hyperbola's vertices (7 units to the left and 7 units to the right from the center). Then draw two branches of hyperbola (one in negative direction and one in positive direction).

3 0

4 years ago

Can someone help me with this? Thanks!

Evgesh-ka [11]

Part (a)

There are 3 face cards (jack, queen, king) in any given suit. We have 4 suits. That gives 3*4 = 12 face cards total.

12/52 = 3/13 is the probability of getting a face card on any random selection. This probably does <u>not</u> change for any future selection because we put the current card back. In other words, the deck has not changed. Contrast this with part (b) where the probabilities will change since the card counts decrease each time (since we don't put the card back).

The probability of getting 3 face cards in a row, with replacement, is:

(3/13)*(3/13)*(3/13) = 0.012289 approximately

This converts to the percentage 1.2289% after moving the decimal point two spots to the right. This is the same as multiplying by 100.

Lastly, round that to one decimal place to get 1.2%

<h3>Answer: 1.2</h3>

The percent sign is already taken care of, so you'll just input the number only.

=============================================================

Part (b)

Like mentioned earlier, the probability of a face card is 12/52

I won't reduce that fraction, as you'll see why below.

After that first card is <u>not</u> put back, the 12 decreases to 12-1 = 11 and we have 52-1 = 51 cards left over.

11/51 is the probability of getting another face card, where we have no replacement going on.

Then 10/50 is the probability of getting a third face card. Again, with no replacement.

Therefore,

(12/52)*(11/51)*(10/50) = 0.009955

is the approximate probability of getting 3 face cards in a row with no replacement. Notice the count down 12,11,10 in the numerators. There's also the countdown 52, 51, 50 in the denominators. This nice pattern only happens if we don't reduce the reducible fractions. This is why I didn't reduce.

Anyways 0.009955 converts to 0.9955% which rounds to 1.0% or simply 1%

<h3>Answer: 1</h3>

4 0

2 years ago

I-6I = <br><br> (whats the answer and show your work)

Tomtit [17]

Answer:

um i think it's 5l

cause l=1

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3 years ago

Read 2 more answers

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Lady_Fox [76]

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3 years ago