Answer:
p = 0.07
p-hat = 0.035
p0 = 0.07
p-value = 0.003
Step-by-step explanation:
p = population parameter, in this case, the rate of infestations across all trees in the forest
p-hat = test statistic, in this case, the rate of infestations found in the sample of trees, i.e. those in Doug's backyard
p0 = the null hypothesis, in this case, the rate of infestations within the forest is correctly evaluated at 0.07 or 7%
p-value = the likelihood any difference between p and p-hat is down to chance
In this case 0.003 as the p-value means there is only 0.3% probability of our statistic value of 0.035 being down to variability and chance meaning it is 99.7% likely that there is some reason behind this difference;
We would accept the alternative hypothesis which says the current parameter value, 0.07, is in fact incorrect (either too high or too low, in this case, likely too high).
I’m pretty sure it’s x-3y over 2
Answer:
5x^2 + 20x = 5x(x + 4)
Step-by-step explanation:
Here, we want to factorize;
5x^2 + 20x
To do this, we start by writing the common factors
The common actor that we can see which is in the form of the gcf of both is 5x
Thus, the factorization will be;
5x^2 + 20x = 5x( x + 4)
I'm using PEDMAS.
Multiplication first.
2 • 4 = 8
Subtraction.
20 - 4 = 16
16 + 8 = 24
Please let me know if you spot any errors (especially the fraction operation)
Answer:i dont think so
Step-by-step explanation:
