All categories

3 years ago

Sara ordered 2 slices of pizza and a 12-ounce cola and paid

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

5 0

Answer: a slice of pizza cost $1.25 and a 12-ounce cola cost $0.50.

Step-by-step explanation:

Let slice of pizza cost x and a 12-ounce cola cost y.

Then Sara's order cost: 2x+y=3

and Sydney's order cost: 3x+2y=4.75

From the first equation we have: y=3-2x and put this to the second equation:

3x+2(3-2x)=4.75

3x+6-4x=4.75

x=1.25

y=3-1.25*2=0.50

Answer: a slice of pizza cost $1.25 and a 12-ounce cola cost $0.50.

You might be interested in

Two angles are vertical angles. If the angles are also complementary angles, what is the degree of the angle

jeyben [28]

Vertical angles are congruent according to the vertical angles theorem. If they are complementary as well, then they both sum up to 90 degrees. So, form an algebraic equation!

x+x=90 or 2x=90... Using the division property of equality, the angle measure (or x) equals 45...

Happy Solving!

4 0

3 years ago

Mr. Ramone brought home 12 of an apple pie from work. He wants to share the apple pie equally among his 6 friends. Type the amou

Svet_ta [14]

Answer:

1/6 each

Step-by-step explanation:

I think this might be the answer.

4 0

3 years ago

The ratio of cats and dogs at the animal shelter is 4 to 5. How many cats could there be? How many dogs? Write six different ans

garik1379 [7]

Answer:

8 cats 10 dogs, 12 cats 15 dogs, 16 cats 20 dogs, 20 cats 25 dogs, 24 cats 30 dogs

Step-by-step explanation:

3 0

3 years ago

he Nassau Bahamas Community College (NBC) claims that students who take statistics spend on average 19 hours a week working. The

Virty [35]

Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that the students' claim that they work more than 19 hours is correct.

At the null hypothesis, it is tested if they spend on average 19 hours a week working, that is:

$H_0: \mu = 19$

At the alternative hypothesis, it is tested if they spend more than 19 hours a week working, that is:

$H_1: \mu > 19$

We have the standard deviation for the sample, hence, the t-distribution is used.

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

Searching the problem on the internet, it is found that the values of the parameters are:

$\overline{x} = 24.2, \mu = 19, s = 12.59, n = 25$

Hence, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{24.2 - 19}{\frac{12.59}{\sqrt{25}}}$

$t = 2.07$

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05 and 25 - 1 = 24 df is of $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that the students' claim that they work more than 19 hours is correct.

To learn more about the t-distribution, you can take a look at brainly.com/question/13873630

3 0

3 years ago

Use laws of exponents to simplify inside the parentheses of the given expression ((a ^ - 2 * b ^ 2)/(a ^ 2 * b ^ - 1)) ^ - 3

Annette [7]

Answer:

$(\dfrac{a ^{ - 2 } b ^ 2}{a ^ 2 b ^ {- 1}}) ^ {- 3}=(a^{-2-2}b^{2+1})^-3=(a^{-4}b^{3})^{-3}=a^{12}b^{-9}$

Step-by-step explanation:

hope this helps

6 0

4 years ago