The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer:
i pretty sure its 6
8x
Step-by-step explanation:
i did the research
Answer:
10 bugs
Step-by-step explanation:
If last month the spider ate 8 bugs, and this month the spider ate 25% more bugs, we can calculate the amount of bugs the spider ate this month finding how much is 25% of 8 bugs, and them we sum this value to the 8 bugs it ate last month.
25% of 8 = 8 * 25 / 100 = 2
Now we know that the spider ate 2 more bugs, so the amount of bugs it ate this month is 8 + 2 = 10 bugs.
We can also solve this problem multiplying directly 8 by 1.25 (1.25 represents the 25% increase in the bug consumption):
8 * 1.25 = 10 bugs.