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Natalka [10]
3 years ago
9

Divide x^4 + 2x^2 + 1 by x+1 .​

Mathematics
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

=x^3-x^2+3x-3+\frac{4}{x+1}

Step-by-step explanation:

\frac{x^4+2x^2+1}{x+1}\\\mathrm{Divide}\:\frac{x^4+2x^2+1}{x+1}:\quad \frac{x^4+2x^2+1}{x+1}=x^3+\frac{-x^3+2x^2+1}{x+1}\\=x^3+\frac{-x^3+2x^2+1}{x+1}\\\mathrm{Divide}\:\frac{-x^3+2x^2+1}{x+1}:\quad \frac{-x^3+2x^2+1}{x+1}=-x^2+\frac{3x^2+1}{x+1}\\=x^3-x^2+\frac{3x^2+1}{x+1}\\\mathrm{Divide}\:\frac{3x^2+1}{x+1}:\quad \frac{3x^2+1}{x+1}=3x+\frac{-3x+1}{x+1}\\=x^3-x^2+3x+\frac{-3x+1}{x+1}\\\mathrm{Divide}\:\frac{-3x+1}{x+1}:\quad \frac{-3x+1}{x+1}=-3+\frac{4}{x+1}\\=x^3-x^2+3x-3+\frac{4}{x+1}

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2 years ago
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Given:

The set of pair and graphs.

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The domain and range.

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We know that,

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Range is the set of y-values or output values.

(a)

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{(-3,3),(5,5),(-3,2),(5,3)}

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(b)

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(c)

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So she will need 17 more pages if she uses the red book.

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3 years ago
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