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2 years ago

Moussa delivered 3/8 of the newspapers on his route in the first hour and 4/5 of the rest in the second hour.

Mathematics

2 answers:

slega [8]2 years ago

8 0

3/8+4/5= 1 7/40 or 47/40

3/8=15/40

4/5=32/40

drek231 [11]2 years ago

3 0

Answer: 3/8 + 4/5 = <u>1 7/40</u>

4/5 = 32/40

3/8 = 15/40

32/40 + 15/40 = 47/40

47/40 = $1\frac{7}{40}$

Hope this helped! Have a great day! :D

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Step-by-step explanation:

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3 years ago

Which value of x makes the equation 0.5(x + 16) = 3 + 0.25(x – 4) true?

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3 years ago

How do you write 8/9 as a decimal?

gladu [14]

Answer:

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3 years ago

Read 2 more answers

Ubi made a banana cream pie.His brother ate 1/3 of the pie and his sister ate 2/6 of the pie.

tamaranim1 [39]

2/3 of the pie had been eaten, there is 1/3 left

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3 years ago

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

4 years ago