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xxMikexx [17]
3 years ago
10

A sports company randomly sends out various cards of 8 different sports,

Mathematics
1 answer:
natima [27]3 years ago
7 0

Answer:

The given situation can be modeled by a simulation that has 8 different possible outcomes and each outcome has the same probability of occurrence. Design a spinner having 8 equal sections and label each section with a different sports card.

Step-by-step explanation:

A sports company randomly sends out various cards of 8 different sports.

We are asked to describe a model that could be used to simulate which sport would be sent out.

The given situation can be modeled by a simulation that has 8 different possible outcomes and each outcome has the same probability of occurrence.

Design a spinner having 8 equal sections and label each section with a different sports card.

Therefore, by spinning the spinner, we can randomly select a sports card that should be sent out from a total of 8 sport cards.

The simulation may be repeated as per the required number of times.

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worty [1.4K]

Answer:

Therefore the probability that a pen from the first box and a crayon from the second box are selected is \frac5{16}

Step-by-step explanation:

Probability:

The ratio of the number of favorable outcomes to the number all possible outcomes of the event.

Probability=\frac{\textrm{The number favorable outcomes}}{\textrm{The number all possible}}

Given that,

Three plain pencils and 5 pens are contained by the first box.

Total number of pens and pencils is =(3+5)=8

The probability that a pen is selected from the first box is

=P(A)

=\frac{\textrm{The number pens}}{\textrm{Total number of pens and pencils}}

=\frac{5}{8}

A second box contains three colored pencils and three crayons.

Total number of pencils and crayons is =(3+3)=6

The probability that a crayon is selected from the second box is

=P(B)

=\frac{\textrm{The number of crayon}}{\textrm{Total number of crayons and pencils}}

=\frac{3}{6}

Since both events are mutually independent.

The required probability is multiple of the events

Therefore the required probability is

=\frac58\times \frac36

=\frac5{16}

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%20%5Cdiv%202%20%5Csqrt%7B2%7D%20" id="TexFormula1" title="5 \div 2 \sqrt{2} " alt="5 \div 2
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\dfrac{5}{2 \sqrt{2} }

it's the only ans then possible ! ^•,,,•^

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X/w = z/y². solve for y​
jek_recluse [69]

Answer:

Step-by-step explanation:

We can simplify (cross multiply) to get xy^2=wz

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8 0
3 years ago
A ball is thrown into the air. The height in feet of the ball can be modeled by the equation, h(t) = −16t2 + 10t + 6 where t is
Lelechka [254]

A function assigns the value of each element of one set to the other specific element of another set. The correct option is D.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

The time at which the ball will hit the ground is,

h(t) = −16t² + 10t + 6

0 = -16t² + 10t + 6

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Learn more about Function:

brainly.com/question/5245372

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