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const2013 [10]
2 years ago
12

The following exercise refers to choosing two cards from a thoroughly shuffled deck. Assume that the deck is shuffled after a ca

rd is returned to the deck.
If you do not put the first card back in the deck before you draw the next, what is the probability that the first card is a club and the second one is black? (Enter your probability as a fraction.)
Mathematics
1 answer:
Andrew [12]2 years ago
6 0

Using it's concept, it is found that there is a \frac{13}{102} probability that the first card is a club and the second one is black.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem:

  • In a deck, there are 52 cards, of which 13 are clubs, hence P(A) = \frac{13}{52} = \frac{1}{4}.
  • Then, of the remaining 51 cards, 26 are black, hence P(B) = \frac{26}{51}.

Then:

p = P(A)P(B) = \frac{1}{4} \times \frac{26}{51} = \frac{13}{102}

\frac{13}{102} probability that the first card is a club and the second one is black.

More can be learned about the probability concept at brainly.com/question/15536019

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