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Dmitriy789 [7]
3 years ago
14

Write an exponential function in the form y=ab^xy=ab x

Mathematics
2 answers:
AnnyKZ [126]3 years ago
7 0

Answer:

y = 16*2^{x}

Step-by-step explanation:

We want an exponential function in the following format:

y = ab^{x}

Goes through the point (0,16).

This means that when x = 0, y = 16

So

y = ab^{x}

16 = ab^{0}

Since b^{0} = 1

a = 16

So

y = 16b^{x}

Goes through the point (7,2048).

This means that when x = 7, y = 2048

Then

y = 16b^{x}

2048 = 16b^{7}

b^{7} = \frac{2048}{16}

b^{7} = 128

b = \sqrt[7]{128}

b = 2

So the function is:

y = 16*2^{x}

AnnyKZ [126]3 years ago
4 0

Answer:

y = 16*2^{x}

Step-by-step explanation:

For this case we have two points given (0,16) and (7,2048). And we want to find a function given by this general expression:

y= ab^x

And using the first point given we have:

16 = a b^0  a = 16

Now we can use the info from the second point and we have:

2048 = 16 b^7

We can divide 16 in both sides and we got

128=b^7

And using an exponent 1/7 in both sides we got:

(128)^{1/7} = b b = 2

And then our model would be given:

y = 16*2^{x}

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Answer:

B. & E.

Step-by-step explanation:

First, to find your slope, put your line into slope-intercept form.

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3x-4y=7\\-4y=-3x+7\\y=\frac{3}{4} x-\frac{7}{4}

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If you put B into slope-intercept form, you get the following:

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