3 years ago

I have a maths problem : Simplify x+x+y x y I’m not sure how to work it out! Please help!

Mathematics

1 answer:

maks197457 [2]3 years ago

8 0

Answer:

$2x+y^2$

Step-by-step explanation:

For this, you check to see if any of these variables are the same. There are two x's, and 2 y's. So, you have to multiply x and x, which gives you 2x, and since you multiply the y's it will give you y^2.

So the answer will be $2x+y^2$

You might be interested in

There are 20 mice in a 5 m2 field ecosystem. The population density of mice is _____.

Alex17521 [72]

The formula for density = number/ area
In this case number=20
area = 5m^2

Density = 20/5=4 mice per m^2
The right answer is <span>A. 4 per m2</span>

6 0

3 years ago

Please Help Me I Only Have 30 Minutes Left

iVinArrow [24]

I pretty sure it’s B

6 0

3 years ago

Given (0,1) and (2, 4). The slope between the two points is ...The equation of the line through the two points is

liubo4ka [24]

Answer:

3/2

Step-by-step explanation:

because the equations y 2 - y 1 over x 2 - x 1 is 4-1 over 2-0 and that is 3/2

3 0

3 years ago

Solve the inequality <br><br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%7D%7Bx%20%2B%203%7D%20%20%5Cleqslant%203" id="Tex

Fofino [41]

$Domain:x\neq-3\\\\\dfrac{2x}{x+3}\leq3\qquad\text{subtract 3 from both sides}\\\\\dfrac{2x}{x+3}-3\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3(x+3)}{x+3}\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3x+9}{x+3}\leq0\\\\\dfrac{2x-(3x+9)}{x+3}\leq0\\\\\dfrac{2x-3x-9}{x+3}\leq0\\\\\dfrac{-x-9}{x+3}\leq0\Rightarrow(x+3)(-x-9)\leq0\\\\x=-3,\ x=-9\\\\x\in(-\infty,\ -9]\ \cup\ (-3,\ \infty)$

3 0

3 years ago

If the length of the side of a square is 3×-y what is the area of the square in terms of x and y

soldier1979 [14.2K]

(3x -y)(3x-y )= 9x^2 - 6xy + y^2

5 0

3 years ago