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Dominik [7]
3 years ago
11

A jar contains 100 tickets for a drawing. Among those tickets are 7 winning tickets. What are the odds in favor of winning?

Mathematics
1 answer:
noname [10]3 years ago
3 0

Answer:

i say 7/100

Step-by-step explanation:

if the 100 tickets is your total then its your denominator

the 7 is represents the tickets what are winners

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Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

8 0
2 years ago
Fill out the ratio table boys 20 and girls 120
Gennadij [26K]

Answer:6

Step-by-step explanation:

You will divide 120/20

5 0
3 years ago
In the circle below, EG is a diameter and EF is tangent at E. Suppose mEF = 124°. Find the following. Does anyone know this?
Ludmilka [50]

Answer:

Step-by-step explanation:

If EG is a diameter, then arc EFG is a semicircle and its measure is 180. Arc FG then is 180 - 124 = 56. Since angle FEG is an inscribed angle and the arc it cuts off is arc FG, then the measure of the inscribed angle is half the measure of the arc it cuts off...so angle FEG is 28 degrees. Keep that in mind; we'll need it in a sec.

If HE is tangent to the circle at E, then angle HEG is a 90 degree angle. Adding that to angle FEG will give you angle FEH. Angle FEH = 90 + 28 = 118

8 0
3 years ago
U need question problem 2 to solve problem 3
Sergio [31]

Answer:

You are correct

Step-by-step explanation:

Start with 1 1/2. This can be made into an improper fraction which is 3/2

Now multiply both top and bottom of 3/2 by 5

(3*5)/(2 * 5) = 15 / 10

16/10 is just slightly bigger than 15/10

3 0
3 years ago
Read 2 more answers
A survey of 2,000 doctors showed that an average of 3 out of 5 doctors use brand X aspirin. How many doctors use brand X aspirin
VladimirAG [237]
This is a proportion problem that involves cross-multiplication
Set your problem up like so:
\frac{x}{2,000} = \frac{3}{5}

Now cross multiply
2,000 x 3 = 6,000
now you're left with 5x = 6,000
Now divide by 5 on both sides
Answer is 1,200
7 0
3 years ago
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